C₂H₂ + N¥₂ + 20₁₂ → C₂ H₂ N = 3H/₂C The feed to propylene anmoxidation off process Contain's 10.0 mole to propy keactional propylene 78.0% air. A ammonia Conversion of 30.0% of the limiting reactant 15 achieved. Taking 100 mul of feed to was a bans determine which reacfunt 15 limiting, gar and the molar amounts of all for a 305 conversion of the limiting reactant constituents determine the molar amounts in atomic species balancer and balancen specier molecular Goswers reactor 100 AN 6.100 Mala4/6/21/ 6120 M N / 3/out Sonsona/nol 021) 02/n air [ 0.71 N₂/olair) Mesto (AJ) (H₂) ANYS Pons (mul Ni13) hot (mot Oc) naz (MoN₂) M²3 13 N (M³) (3H₂N) Muss (Md the) answersi Da₂H² 7₂0 mu) (₂) 1/x C 104

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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chemical processes:  reactive balances

C3H6 + NH₂ + 2₂20₂ C3 Hz № + 37/₂
NH302
N
The feed to propylene anmoxidation of
process contain's 10,0 mole 70 propylene,
ammonia,
fractional
Conversion of 30.0% of the limiting reactant
15 achieved. Taking 100 mul of feed was a
bans determine which reactant 15 limiting
and the molar amounts of all gar aunotituents
for a 30% Conversion of the limiting reactant.
determine the molar, amounts in
atomic species balancer and
molecular specier balancen
Gooswers
reactor
100 AN
6.100 ml ₂4/0/ANT
GIS MY N/₂/out
Sonsum argnd I
62/mo) 0₂/no air
6,79 mul N₂1 mol air
[
Mesto (n) (16)
PWHS (mu) N₁13)
ANYS
hot (md Oc)
MAL (MAN₂)
MC₂513 N (M³) (3H₂N)
nuns (mo the)
answers. Dato ² 7.0 mu) (3) 1x
ning ² 9. J mul MM3
no₂² 11,9 mol O₂
AN 61.6 mI NE
nzn₂ N = 3,00 m√ GM₂N
MNE Col. 6 mol N₂
2
no 9. U mul M2d
Transcribed Image Text:C3H6 + NH₂ + 2₂20₂ C3 Hz № + 37/₂ NH302 N The feed to propylene anmoxidation of process contain's 10,0 mole 70 propylene, ammonia, fractional Conversion of 30.0% of the limiting reactant 15 achieved. Taking 100 mul of feed was a bans determine which reactant 15 limiting and the molar amounts of all gar aunotituents for a 30% Conversion of the limiting reactant. determine the molar, amounts in atomic species balancer and molecular specier balancen Gooswers reactor 100 AN 6.100 ml ₂4/0/ANT GIS MY N/₂/out Sonsum argnd I 62/mo) 0₂/no air 6,79 mul N₂1 mol air [ Mesto (n) (16) PWHS (mu) N₁13) ANYS hot (md Oc) MAL (MAN₂) MC₂513 N (M³) (3H₂N) nuns (mo the) answers. Dato ² 7.0 mu) (3) 1x ning ² 9. J mul MM3 no₂² 11,9 mol O₂ AN 61.6 mI NE nzn₂ N = 3,00 m√ GM₂N MNE Col. 6 mol N₂ 2 no 9. U mul M2d
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