ch, choose its equation from the following. = sec (x+²) = y = cot (x + ²) 4 v=2 tan x 2 y=-csc x 1 T T T i I -X+ -2- A 3x5x 4 4 4 1 I i I 77 4 9x 4 px 11x| 1 4 1 T I 1 T I I I I y=2 tan x y = csc x 2- 2 -2- -4- I t " 1 * 3x 2 2x 5% 3x 5x 4 7x1 4 I I 9m 11

Q: 1 |dx I (sec² x csc* x.

A: Integration gives the function whose derivative is given. It is nothing but adding all to make…

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A:

Q: S(csc x cot x + 9x°)dx Csc x + x° +c - sec x + x³ +c | CSc x + x9 - sin x + x³ +c sec x + r9 + c

A:

Q: cosx/secx+tanx

A: The given expression is:

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A:

Q: y=sin(x−y)

A:

Q: csc(sec-1 2) + cos(tan-(-v3).

A: Given data:     The expression for the given function is: csc(sec-12)+cos(tan-1(-31⁄2).   The given…

Q: y= (1+ tan ()

A:

Q: Y = 2 sin x + 1

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Q: Manipulate In|sec x + tan x|| so that it is expressed as a difference of logs.

A:

Q: y = 8 tan 5x + 4 cos 3x + 11secx

A:

Q: sec x tanx (1+sec'x)² + sec

A: substitute u= sec3(x)+1 du/dx=3sec3(x)tan(x) dx = du/(3sec3(x)tan(x)) put this in equation  1/3∫…

Q: (a) y = = tan a 18

A: To differentiate the following function.