**Distinguishing Molecules Using Infrared (IR) Spectroscopy****Question:**Which choice best explains why the molecules below can be distinguished by IR?**Image Description:**The image shows structural formulas of two molecules labeled Molecule A and Molecule B. Molecule A is benzaldehyde consisting of a benzene ring with an attached aldehyde group (CHO). Molecule B is acetophenone with a benzene ring attached to a ketone group (COCH₃).**Multiple Choice Options:**A. Molecule A has a peak just above 3000 cm⁻¹ and Molecule B does not.B. Molecule A has a peak for an aldehyde around 2200 cm⁻¹ and Molecule B does not.C. Molecule B has a carbonyl peak around 1750 cm⁻¹ and Molecule A does not.D. Molecule A and Molecule B can't be easily distinguished by IR.**Explanation:**Infrared (IR) spectroscopy is a technique used to identify and study chemicals by measuring the absorption of infrared radiation at different frequencies. Certain functional groups within molecules absorb characteristic frequencies of infrared light, which appear as peaks in an IR spectrum.- **Option A:** Molecule A has a peak just above 3000 cm⁻¹ due to the C-H stretching in the aldehyde group. Molecule B, which has a ketone group instead, will not have this peak.- **Option B:** Aldehydes typically show a peak around 1725 cm⁻¹ for C=O stretching, not at 2200 cm⁻¹, so this statement is not correct.- **Option C:** Ketones show a strong carbonyl (C=O) peak near 1715 cm⁻¹, so Molecule B will have such a peak; but Molecule A, which also contains a carbonyl group, will have overlapping peaks making option C less specific.- **Option D:** This statement is incorrect as IR spectroscopy can distinguish the functional groups present in these molecules.Accordingly, the correct answer is **Option A**.This explanation helps us understand how to use IR spectroscopy to differentiate between molecules with similar but distinct functional groups based on their unique absorption peaks.

We have two molecules present, Molecule A is aldehyde whereas Molecule B is ketone.

ch choice best explains why the molecules below can be distinguished by IR H Molecule A Molecule A has a peak just above 3000 cm" and Molecule B does not Molecule A has a peak for an aldehyde around 2200 cm" and Molecule B does not Molecule B has a carbonyl peak around sa cm and Molecule A does not Molecule A and Molecule B can't be easily distinguished by IR CH₂ Molecule B

ch choice best explains why the molecules below can be distinguished by IR H Molecule A Molecule A has a peak just above 3000 cm" and Molecule B does not Molecule A has a peak for an aldehyde around 2200 cm" and Molecule B does not Molecule B has a carbonyl peak around sa cm and Molecule A does not Molecule A and Molecule B can't be easily distinguished by IR CH₂ Molecule B

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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