:: Center: (2,3) - Circumference = 87 :: Center: (-3,3) - Radius = V17 %3D :: Center: (2,3) - Radius: 2 :: Center: (1,2) Diameter: 6 : Center: (-3,3) - Area = 25T :: Center (1,2) - Area %3D Зп ::

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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Question
ll T-Mobile
9:40 AM
E Circle Equation and Properties...
:: Center: (2,3) - Circumference = 87T
%D
:: Center: (-3,3) - Radius = v17
:: Center: (2,3) - Radius: 2
:: Center: (1,2) Diameter: 6
:: Center: (-3,3) - Area = 257
:: Center (1,2) - Area %3D Зп
::
Transcribed Image Text:ll T-Mobile 9:40 AM E Circle Equation and Properties... :: Center: (2,3) - Circumference = 87T %D :: Center: (-3,3) - Radius = v17 :: Center: (2,3) - Radius: 2 :: Center: (1,2) Diameter: 6 :: Center: (-3,3) - Area = 257 :: Center (1,2) - Area %3D Зп ::
.ll T-Mobile
9:40 AM
E Circle Equation and Properties...
Match the Equation to the given to the
properties
(x – 2)² + (y – 3)² = 4
-
(x + 3)² + (y – 3)² = 17
(x – 1)² + (y – 2)² = 9
-
L -
(x – 2)? + (y – 3)² = 16
(x + 3)² + (y – 3)² = 25
-
(x – 1)² + (y – 2)² = 3
-
(x + 3)² + (y – 6)² = 4
x² + (y + 2)² = 36
- → Q X
Transcribed Image Text:.ll T-Mobile 9:40 AM E Circle Equation and Properties... Match the Equation to the given to the properties (x – 2)² + (y – 3)² = 4 - (x + 3)² + (y – 3)² = 17 (x – 1)² + (y – 2)² = 9 - L - (x – 2)? + (y – 3)² = 16 (x + 3)² + (y – 3)² = 25 - (x – 1)² + (y – 2)² = 3 - (x + 3)² + (y – 6)² = 4 x² + (y + 2)² = 36 - → Q X
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