**Problem 9**: A baseball of mass \( m_1 = 0.28 \, \text{kg} \) is thrown at another ball hanging from the ceiling by a length of string \( L = 1.1 \, \text{m} \). The second ball \( m_2 = 0.61 \, \text{kg} \) is initially at rest, while the baseball has an initial horizontal velocity of \( V_1 = 2.5 \, \text{m/s} \). After the collision, the first baseball falls straight down (no horizontal velocity).**Randomized Variables**- \( m_1 = 0.28 \, \text{kg} \)- \( m_2 = 0.61 \, \text{kg} \)- \( L = 1.1 \, \text{m} \)- \( V_1 = 2.5 \, \text{m/s} \)### Diagram ExplanationThe diagram illustrates a scenario where:1. A ball \( m_1 \) is moving horizontally towards another ball \( m_2 \).2. \( m_2 \) is hanging from a string of length \( L \).3. After the collision, \( m_2 \) swings upwards, and its maximum height is indicated by the angle \( \theta \).### Part (a)Select an expression for the magnitude of the closest distance from the ceiling the second ball will reach \( d \).Options:1. \( d = L - \frac{V_1^2}{2g} \)2. \( d = L - \frac{m_1 V_1}{2m_2 g} \)3. \( d = \frac{(m_1 V_1)^2}{2m_2^2 g} \)**Submit**, **Hint**, **Feedback**, **I give up!**### Part (b)What is the angle that the string makes with the vertical at the highest point of travel in degrees?

Name: **Problem 9**: A baseball of mass \( m_1 = 0.28 \, \text{kg} \) is th
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Description: **Problem 9**: A baseball of mass \( m_1 = 0.28 \, \text{kg} \) is thrown at another ball hanging from the ceiling by a length of string \( L = 1.1 \, \text{m} \). The second ball \( m_2 = 0.61 \, \text{kg} \) is initially at rest, while the basebal

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ceiling by a length of string L=1.1 m. The second ball m2= 0.61 kg is initially at rest while the baseball has an initial horizontal velocity of V, = 2.5 m/s. After the collision the first baseball falls straight down (no horizontal velocity). Randomized Variables m1= 0.28 kg m2 = 0.61 kg L=1.1 m V= 2.5 m/s m, m, 20theexpertta.com Part (a) Select an expression for the magnitude of the closest distance from the ceiling the second ball will reach d. d = L- 2g m,V 2m29 (m, V)2 d = d = L- 2m3g (m,V)2 2m2g d = L- Submit Hint Feedback I give up! Part (b) What is the angle that the string makes with the vertical at the highest point of travel in degrees?

ceiling by a length of string L=1.1 m. The second ball m2= 0.61 kg is initially at rest while the baseball has an initial horizontal velocity of V, = 2.5 m/s. After the collision the first baseball falls straight down (no horizontal velocity). Randomized Variables m1= 0.28 kg m2 = 0.61 kg L=1.1 m V= 2.5 m/s m, m, 20theexpertta.com Part (a) Select an expression for the magnitude of the closest distance from the ceiling the second ball will reach d. d = L- 2g m,V 2m29 (m, V)2 d = d = L- 2m3g (m,V)2 2m2g d = L- Submit Hint Feedback I give up! Part (b) What is the angle that the string makes with the vertical at the highest point of travel in degrees?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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A baseball of mass m1 = 0.43 kg is thrown at another ball hanging from the ceiling by a length of string L = 1.65 m. The second ball m2 = 0.97 kg is initially at rest while the baseball has an initial horizontal velocity of V1 = 3.5 m/s. After the collision the first baseball falls straight down (no horizontal velocity).Randomized Variablesm1 = 0.43 kgm2 = 0.97 kgL = 1.65 mV1 = 3.5 m/s Part (a) Select an expression for the magnitude of the closest distance from the ceiling the second ball will reach d. Part (b) What is the angle that the string makes with the vertical at the highest point of travel in degrees?
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