CEE 241: Statics University of Nevada, Las Vegas Image copyright © Pearson Education, Inc. Shared with current students using accompanying text by the instructor solely for the purpose of teaching the course and assessing student learning. You should not distribute this document to anyone. Determine the force in each member of the truss. Interpret your results to state whether each member is in tension or compression. -3 ft- + -3 ft B D 4 ft 4 ft W E "Ba 13/12 130 lb Answer: AB= 140 lbf (T) AC = 150 lbf (C) BC = 0 BD = 140 lbf (T) CD = 150 lbf (T) -3 ft- CE = 180 lbf (C) DE = 120 lbf (C) DF = 230 lbf (T) EF = 300 lbf (C)

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**CEE 241: Statics**

University of Nevada, Las Vegas

*Image copyright © Pearson Education, Inc. Shared with current students using accompanying text by the instructor solely for the purpose of teaching the course and assessing student learning. You should not distribute this document to anyone.*

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**Problem Statement:**

Determine the force in each member of the truss. Interpret your results to state whether each member is in tension or compression.

**Diagram Explanation:**

The diagram shows a truss with members labeled as follows:
- Points are labeled A, B, C, D, E, and F.
- Horizontal distances between points: AB = 3 ft, BC = 3 ft, DE = 3 ft.
- Vertical distance from C to the 130 lb force is 4 ft.
- A force of 130 lb is applied vertically downward on point A.

**Solution:**

For each member of the truss, the force is calculated and its nature (tension or compression) is indicated.

**Answer:**

- Member AB: 140 lbƒ (Tension)
- Member AC: 150 lbƒ (Compression)
- Member BC: 0 lbƒ
- Member BD: 140 lbƒ (Tension)
- Member CD: 150 lbƒ (Tension)
- Member CE: 180 lbƒ (Compression)
- Member DE: 120 lbƒ (Compression)
- Member DF: 230 lbƒ (Tension)
- Member EF: 300 lbƒ (Compression)

This solution provides insight into how forces are distributed throughout the truss structure and indicates which members are in tension and which are in compression.
Transcribed Image Text:**CEE 241: Statics** University of Nevada, Las Vegas *Image copyright © Pearson Education, Inc. Shared with current students using accompanying text by the instructor solely for the purpose of teaching the course and assessing student learning. You should not distribute this document to anyone.* --- **Problem Statement:** Determine the force in each member of the truss. Interpret your results to state whether each member is in tension or compression. **Diagram Explanation:** The diagram shows a truss with members labeled as follows: - Points are labeled A, B, C, D, E, and F. - Horizontal distances between points: AB = 3 ft, BC = 3 ft, DE = 3 ft. - Vertical distance from C to the 130 lb force is 4 ft. - A force of 130 lb is applied vertically downward on point A. **Solution:** For each member of the truss, the force is calculated and its nature (tension or compression) is indicated. **Answer:** - Member AB: 140 lbƒ (Tension) - Member AC: 150 lbƒ (Compression) - Member BC: 0 lbƒ - Member BD: 140 lbƒ (Tension) - Member CD: 150 lbƒ (Tension) - Member CE: 180 lbƒ (Compression) - Member DE: 120 lbƒ (Compression) - Member DF: 230 lbƒ (Tension) - Member EF: 300 lbƒ (Compression) This solution provides insight into how forces are distributed throughout the truss structure and indicates which members are in tension and which are in compression.
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