Cecsrsts coum Mobeend n7 3000 P300hed CO H2 N2- L CLOR-UD ni n2 co, C Reactor n3 NO CD. CO - H2- CH3OH Condenser Fresh feed n1(kmoliday) 1000 Basis 0.3 0.6 01 1000 kmolld VIN2 1 single reaction 2 syngas contains only COH2 and N2 3. basis of 1000 kmolld is used and then upscale according to the production required 4. anticipate recycle to fresh feed ratio of 31 5. 25 mol% of N2 in the recycle n4 CH3CH Stream num rate (kmolld) CO H2 N2 CH30H 2 3 41 5 7 17123.3 4000 61643.8 3424.66 582192 6849.32 51369.9 0.3 0.6 0.1 of 0.26 053 021 0.24 047 024 006 025 0.5 0.25 0.25 0.5 025 0.25 05 025 Step 1 Overall mass balance To find the extent of reaction, all this 3 equation is needed let yacn- find E- 300 - 400yco f-(600 - 400y /2 0.75- Ya. Component mass balance Stream numb molar flow rate (kmolld) 171233 6849.32 N2 9. 2. y1.N2 (n1) = n6(0.25) yaco (n6) = 0.3(1000) -{ CO Yeaz(n6) = 0.6(1000) - 2 H2 1= yeco +yurz +0.25 01 0.3 0.25 0.25 05 equate 1 and 2 300 - 400ycon (600 - 400y/2 06 subsutitute yaco and solved for ya 300 - 400(0.75 - ya) = (600 - 400ya/2 Y=0.50 solved Yaco 0.75 - ya -0.25
Cecsrsts coum Mobeend n7 3000 P300hed CO H2 N2- L CLOR-UD ni n2 co, C Reactor n3 NO CD. CO - H2- CH3OH Condenser Fresh feed n1(kmoliday) 1000 Basis 0.3 0.6 01 1000 kmolld VIN2 1 single reaction 2 syngas contains only COH2 and N2 3. basis of 1000 kmolld is used and then upscale according to the production required 4. anticipate recycle to fresh feed ratio of 31 5. 25 mol% of N2 in the recycle n4 CH3CH Stream num rate (kmolld) CO H2 N2 CH30H 2 3 41 5 7 17123.3 4000 61643.8 3424.66 582192 6849.32 51369.9 0.3 0.6 0.1 of 0.26 053 021 0.24 047 024 006 025 0.5 0.25 0.25 0.5 025 0.25 05 025 Step 1 Overall mass balance To find the extent of reaction, all this 3 equation is needed let yacn- find E- 300 - 400yco f-(600 - 400y /2 0.75- Ya. Component mass balance Stream numb molar flow rate (kmolld) 171233 6849.32 N2 9. 2. y1.N2 (n1) = n6(0.25) yaco (n6) = 0.3(1000) -{ CO Yeaz(n6) = 0.6(1000) - 2 H2 1= yeco +yurz +0.25 01 0.3 0.25 0.25 05 equate 1 and 2 300 - 400ycon (600 - 400y/2 06 subsutitute yaco and solved for ya 300 - 400(0.75 - ya) = (600 - 400ya/2 Y=0.50 solved Yaco 0.75 - ya -0.25
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
Related questions
Question
can you explain to me how to get for the calc that i highlight red
Transcribed Image Text:Unveeced
coum
Mhac Schest
n7
3000
CD.AK.
at
BUDRnoD
n6
CO
H2
N2-
n5
co,, t CLO
Co , CO O
co, CON
14
n1
n2
025 r6)
15
n3
Me
Ka.co,
Reactor
16
CO - H2 - CH3OH
Condenser
Fresh feed
n1(kmolday)
y1.CO
v1H2
yIN2
17
18
1000
0.3
0.6
0.1
Basis
20
1000 kmolld
1 single reaction
2 syngas contains only COH2 and
N2
3. basis of 1000 kmolld is used and
then upscale according to the
production required
4. anticipate recycle to fresh feed
ratio of 31
5. 25 mol% of N2 in the recycle
n4
CH3OH
Stream num
rate
(kmolld)
CO
H2
N2
CH30H
21
4000 61643.8 3424.66 58219.2 6849.32 51369.9
3
17123.3
0.3
0.6
0.1
0.26
0.24
0.53 0.47
0.24
0.06
0.25
05
0.25
0.25
0.5
0.25
0.25
05
0.25
0.21
Step 1
Overall mass balance
Component mass balance
Stream numb
molar flow
rate (kmolld)
N2
CO
To find the extent of reaction, all this 3 equation is needed
let yacn =0.75- ya.
find E
E-300 - 400yaco
-(600 - 400ya/2
6.
2
y1.N2 (n1) = n6(0.25)
yaco (n6) = 0.3(1000) -{
171233 6849.32
0.25
0.25
0.5
equate 1 and 2
01
0.3
300 - 400yco (600 - 400y/2
Yarz(n6) = 0.6(1000) - 2 H2
%3D
0.6
subsutitute yaco and solved for yar
300 - 400(0.75 - yan) - (600 - 400ya/2
Y-0.50
1 = yeco +Yar + 0.25
solved
Yaco -0.75 - yar -0.25
Methanol Synthesis mass balance Energy balance
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