CE1142-2/476 Las Trươn Ag - single, equat leg angle Ae 2 r> - Single line, 4-25mm Ø bolts Pu=12 (125) + 1-6 (375): 750KN or 750,000 N fy = 248 NP₁₂ 750,000 09 (248) : 3360.215 mm² 750,000 2500 mm" 0.75 (40) 5500 : 20 : A36 steel DL: 125 KN LL: 375 KN Length: L: 5.5m USE LRFI) 18:33 мм from ASEP L125 x 125 x 16 properties. = 3762 mm ² Ag = r = 37.7mm Therefore, checking Ae of L125 x 125 x 16 V = 0.8 Ae- 08 [3762-C25+5)(16)] = 2625.6 mm Ae: 2625.62500 37-7 7 18.33 .. Use L125 x 125 x 16 ok Class work 1D September 12, 2023
CE1142-2/476 Las Trươn Ag - single, equat leg angle Ae 2 r> - Single line, 4-25mm Ø bolts Pu=12 (125) + 1-6 (375): 750KN or 750,000 N fy = 248 NP₁₂ 750,000 09 (248) : 3360.215 mm² 750,000 2500 mm" 0.75 (40) 5500 : 20 : A36 steel DL: 125 KN LL: 375 KN Length: L: 5.5m USE LRFI) 18:33 мм from ASEP L125 x 125 x 16 properties. = 3762 mm ² Ag = r = 37.7mm Therefore, checking Ae of L125 x 125 x 16 V = 0.8 Ae- 08 [3762-C25+5)(16)] = 2625.6 mm Ae: 2625.62500 37-7 7 18.33 .. Use L125 x 125 x 16 ok Class work 1D September 12, 2023
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
Can you help me explain step by step how to come up with that answer
![WC, Dan Dexter 6
CEN42-2/476
LOUIS
Problem
Ag
- single, equat leg angle
Ae 2
r>
- Single line, 4-25mm Ø bolts
Pu=12 (125) + 1-6 (375)= 750KN or 750,000 N
fy = 248 NP₁₂
750,000
09 (248)
:
3360.215 mm²
750,000 2500 mm"
0-75 (40)
5500 :
20
:
A36 steel
DL: 125 KN
LL: 375 KN
Length: L: 5.5m
USE LRFI)
18:33 мм
from ASEP
L125 x 125 x 16 properties.
Ag = 3762 mm ²
r = 37.7mm
Therefore, checking Ae of L125 x 125 x 16
V = 0.8
Ae- 08 [3762-(25+5)(16)]
= 2625.6
mm
Ae: 2625.62500
37.7 > 18.33
ok
.. Use L125 x 125 x 16
Class work 1D
September 12, 2023](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3b2e99bc-af2b-4be7-a434-4ecedeb31c1b%2Fd19378cd-1b6d-4d82-b91a-fe730928d534%2F8wc3ee5_processed.jpeg&w=3840&q=75)
Transcribed Image Text:WC, Dan Dexter 6
CEN42-2/476
LOUIS
Problem
Ag
- single, equat leg angle
Ae 2
r>
- Single line, 4-25mm Ø bolts
Pu=12 (125) + 1-6 (375)= 750KN or 750,000 N
fy = 248 NP₁₂
750,000
09 (248)
:
3360.215 mm²
750,000 2500 mm"
0-75 (40)
5500 :
20
:
A36 steel
DL: 125 KN
LL: 375 KN
Length: L: 5.5m
USE LRFI)
18:33 мм
from ASEP
L125 x 125 x 16 properties.
Ag = 3762 mm ²
r = 37.7mm
Therefore, checking Ae of L125 x 125 x 16
V = 0.8
Ae- 08 [3762-(25+5)(16)]
= 2625.6
mm
Ae: 2625.62500
37.7 > 18.33
ok
.. Use L125 x 125 x 16
Class work 1D
September 12, 2023
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