Casino games of pure chance (e.g. craps, roulette, baccarat, and keno) always yield a "house advantage." For example, in the game of double-zero roulette, the expected casino win percentage is 5.34% on bets made on whether the outcome will be either black or red. (This implies that for every $5 bet on black or red, the casino will eam a net of about 34 cents.) It can be shown that in 100 roulette plays on black/red, the average casino win percentage is normally distributed with mean 5.34% and standard deviation 11%. Let x represent the average casino win percentage after 100 bets on black/red in double-zero roulette. Complete parts a through d. a. Find P(x>0). (This is the probability that the casino wins money) P(x > 0) =O (Round to three decimal places as needed.) b. Find P(6

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Casino games of pure chance (e.g. craps, roulette, baccarat, and keno) always yield a house advantage." For example, in the game of double-zero roulette, the
expected casino win percentage is 5.34% on bets made on whether the outcome will be either black or red. (This implies that for every $5 bet on black or red, the
casino will eam a net of about 34 cents.) It can be shown that in 100 roulette plays on black/red, the average casino win percentage is normally distributed with mean
5.34% and standard deviation 11%. Let x represent the average casino win percentage after 100 bets on black/red in double-zero roulette. Complete parts a through d.
a. Find P(x>0). (This is the probability that the casino wins money)
P(x> 0) =D (Round to three decimal places as needed.)
b. Find P(6 <x< 15).
P(6 <x< 15) =D (Round to three decimal placeos as needed.)
)%3D
c. Find P(x<2).
P(x< 2) =O (Round to three decimal places as noeded.)
d. If you observed an average casino win percentage of -25% after 100 roulette bets on black/red, what would you conclude?
O A. The probability of an average casino win percentage of - 25% is very small, near 0. The casino is losing money.
O B. The probability of an average casino win percentage of - 25% is very large, near 1. The casino is losing money.
OC. The probability of an average casino win Dercentage of - 25% is very large, near 1. The casino is winning money.
O D. The probability of an average casino win percentage of - 25% is very small, near 0. The casino is winning money
Transcribed Image Text:Casino games of pure chance (e.g. craps, roulette, baccarat, and keno) always yield a house advantage." For example, in the game of double-zero roulette, the expected casino win percentage is 5.34% on bets made on whether the outcome will be either black or red. (This implies that for every $5 bet on black or red, the casino will eam a net of about 34 cents.) It can be shown that in 100 roulette plays on black/red, the average casino win percentage is normally distributed with mean 5.34% and standard deviation 11%. Let x represent the average casino win percentage after 100 bets on black/red in double-zero roulette. Complete parts a through d. a. Find P(x>0). (This is the probability that the casino wins money) P(x> 0) =D (Round to three decimal places as needed.) b. Find P(6 <x< 15). P(6 <x< 15) =D (Round to three decimal placeos as needed.) )%3D c. Find P(x<2). P(x< 2) =O (Round to three decimal places as noeded.) d. If you observed an average casino win percentage of -25% after 100 roulette bets on black/red, what would you conclude? O A. The probability of an average casino win percentage of - 25% is very small, near 0. The casino is losing money. O B. The probability of an average casino win percentage of - 25% is very large, near 1. The casino is losing money. OC. The probability of an average casino win Dercentage of - 25% is very large, near 1. The casino is winning money. O D. The probability of an average casino win percentage of - 25% is very small, near 0. The casino is winning money
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