Caselet #1 CONCRETE STRENGTH The strength of concrete depends, to some extent, on the method used for drying. Two different drying methods showed the following results for independently tested specimens (measurements in psi): Do the methods appear to produce concrete with different mean strengths? Use a = 0.05. %3D Method I n = 37 ž, = 3.25 sz = 2.10 Method II n2 = 40 žz = 3.24 S2 = 1.90
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The strength of concrete depends, to some extent, on the method used for drying. Two different drying methods showed the
following results for independently tested specimens (measurements in psi): Do the methods appear to produce concrete with
different mean strengths? Use � = 0.05 .
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- A pet food company is concerned that their pet food must have a certain % of the mineral zinc in the food. Too little and dogs get very sick. If the machinery is working correctly, the average zinc is u = .375 gram/lb of food. They sample 25 bags of food and find: i = .359 grams o = .05 grams The firm wants to know if their pet food is healthy. They decide on a 95% level of significance. Do the Z test. They ask you to perform the analysis. a) State the null and alternative hypotheses. Ho: На: b) Draw a picture/graph of what you are trying to find. c) Find the critical value you will use. d) Compute the test statistic (from the data) e) What do you conclude? Why?The average life expectancy of tires 40,000 miles. The company has rece The manager hopes to find out wheth life test, 40 tires were used, and their following SPSS results: One-Sample Statistics Std. Dev Mean time 40881.8262 40 2945 One- df Sig. (2-taile 1.893 Set up Ho: M = 40,000 %3D HA: The test statistic is 1.893 The distribution of the test stati Make the statistical decision (o Express the statistical decision1. Analyze the data as a two way factorial design. Johnson and Leone (Statistics and Experimental Design in Engineering and the Physical Sciences, Wiley, 977) describe an experiment to investigate warping of copper plates. The two factors studied were the temperature and the copper content of the plates. The response variable was a measure of the amount of warping. The data were as follows: Temperature (°C) 50 75 100 125 40 17, 20 12,9 16, 12 21, 17 Copper Content (%) 60 80 16, 21 18, 13 18, 21 23, 2! 24, 22 17, 12 25, 23 23, 22 100 28, 27 27, 31 30, 23 29, 31
- Researchers were interested in assessing whether stress levels are different at the beginning of the semester compared to finals week. To test this, stress was measured in 5 students at the start of the semester and then again at the end of the semester during finals week. Participant Stress 1 Stress 2 1 22 22 2 32 34 3 24 25 4 28 30 5 26 29 Then H0: μ2 - μ1 ≠ 0, true or false?Please don’t use excelProvide what is required for the following: (Show your solution) 1. The data below are the shoot lengths (cm.) of Robusta coffee seedlings as affected by different periods of storage. Find out if there are significant differences in the effects of different periods of storage on the shoot lengths. (Note: CRD experiment) Solve for the; a. F computed b. Coefficient of Variation (CV), c. Standard error of the treatment means (S,), d. standard error of difference between treatments (Sd) e. Make a Decision Treatments Replications II II P1 10.1 9.2 9.5 P2 9.5 9.3 8.5 P3 8.7 9.2 7.5 P4 6.7 6.2 5.0
- An article reported data from a study in which both a baseline gasoline mixture and a reformulated gasoline were used. Consider the following observations on age (yr) and NOx emissions (g/kWh): Engine 1 2 3 4 5 6 7 8 9 10 Age 0 0 2 11 7 16 9 0 12 4 Baseline 1.70 4.38 4.06 1.24 5.29 0.59 3.35 3.45 0.73 1.22 Reformulated 1.86 5.91 5.51 2.70 6.50 0.71 4.95 4.86 0.72 1.41 Construct scatter plots of the baseline NOx emissions versus age. What appears to be the nature of the relationship between these two variables? There is no compelling relationship between the data. As age increases, emissions also increase. As age increases, emissions decrease.Evaluate the following grades: (Case 1) a grade of 220 points on an exam with u = 200 ando = 21. (Case 2) a grade of 90 points on an exam with µ = 80 and o = 8. * The better grade cannot be determined. The first grade is better. The two grades are equal statistically. The second grade is better.Need help asap pls!!
- Suppose the lengths of human pregnancies are normally distributed with µ = 266 days and o = 16 days. Complete parts (a) and (b) below. ..... (a) The figure to the right represents the normal curve with u = 266 days and o = 16 days. The area to the right of X= 300 is 0.0168. Provide two interpretations of this area. %3D Provide one interpretation of the area using the given values. Select the correct choice below and fill in the answer boxes to complete your choice. (Type integers or decimals.) A. The proportion of human pregnancies that last less than days is O B. The proportion of human pregnancies that last more than days is 266 300 Provide a second interpretation of the area using the given values. Select the correct choice below and fill in the answer boxes to complete your choice. (Type integers or decimals.) O A. The probability that a randomly selected human pregnancy lasts more than days is B. The probability that a randomly selected human pregnancy lasts less than days is (b)…PLEASE ANSWER ALL THE PARTS OF QUESTION (THIS IS NOT A HRADED ASSIGNMENT)Much concern has been expressed regarding the practice of using nitrates as meat preservatives. In one study involving possible effects of these chemicals, bacteria cultures were grown in a medium containing nitrates. The rate of uptake of radio-labeled amino acid (in dpm, disintegrations per minute) was then determined for each culture, yielding the following observations. 7,256 6,876 9,634 6,867 9,091 5,848 7,061 7,491 7,882 8,173 7,521 8,721 8,959 7,973 X 7,463 Suppose that it is known that the mean rate of uptake for cultures without nitrates is 8,000. Do the data suggest that the addition of nitrates results in a decrease in the mean rate of uptake? Test the appropriate hypotheses using a significance level of 0.10. Find the test statistic and P-value. (Use technology to calculate the P-value. Round your test statistic to two decimal places and your P-value to four decimal places.) t = P-value = 0.2142 State your conclusion. O Fail to reject Ho. We have convincing evidence that…