Carnot cycle Он W TH LTc V O 2016 Pearson Education, Inc. processes; and processes and segment ab & cd are the Where segments ad & bc are the the volumes involved are Va, Vb, Vc, Vd, and the two temperatures TC and

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Calculate the efficiency of the Carnot Engine for ideal gas. Consider the figure below for a complete cycle of Carnot engine, where the cycle goes from ad -> ab -> bc -> cd.

 

Where the segments ad & bc are the _______ processes and segment ab & cd are the _______ processes; and the volumes involved are Va, Vb, Vc, Vd, and the two temperatures are TC and _______.

 

Sol.

Since deltaU = 0, then the heat segment ab is

QH = _____TH ln |_____/______|

The heat segment on cd is

QC = -_____TC ln |_____/_____|

 

By inspection, we can say that

THVYb-1 = _______VYc-1

and

TH_______Y-1 = _______VYd-1

 

Thus,

Vb/_______ - _______/_______

Then,

|QC-QH| = |_______/_______|

 

which solves the efficiency of the carnot engine.

Thus,
Vb/
=
then
|QC/QH| = |
%3D
Which solves the efficiency of the Carnot engine.
Transcribed Image Text:Thus, Vb/ = then |QC/QH| = | %3D Which solves the efficiency of the Carnot engine.
Calculate the efficiency of the Carnot Engine for ideal gas. Consider the figure below for a complete cycle of Carnot engine, where the cycle
goes from ad->ab->bc->cd
Carnot cycle
Он
W
TH
Tc
© 2016 Pearson Education, Inc.
Where segments ad & bc are the
processes and segment ab & cd are the
processes; and
the volumes involved are Va, Vb, Vc, Vd, and the two temperatures TC and
Sol.
Since AU = 0, then the heat on segment ab is
QH =
TH I |
The heat on segment cd is
QC = -
TC In |
By inspection, we can say that
VY-1
%3D
and
Y-1_
TH
Transcribed Image Text:Calculate the efficiency of the Carnot Engine for ideal gas. Consider the figure below for a complete cycle of Carnot engine, where the cycle goes from ad->ab->bc->cd Carnot cycle Он W TH Tc © 2016 Pearson Education, Inc. Where segments ad & bc are the processes and segment ab & cd are the processes; and the volumes involved are Va, Vb, Vc, Vd, and the two temperatures TC and Sol. Since AU = 0, then the heat on segment ab is QH = TH I | The heat on segment cd is QC = - TC In | By inspection, we can say that VY-1 %3D and Y-1_ TH
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