carnival game is designed so that approximately 10% of players will win a large prize. If there is evidence that the percentage differs significantly from this target, then adjustments will be made to the game. To investigate, a random sample of 100 players is selected from the large population of all players. Of these players, 19 win a large prize. The question of interest is whether the data provide convincing evidence that the true proportion of players who win this game differs from 0.10. The computer output gives the results of a z-test for one proportion. Test and CI for One Proportion Test of p = 0.1 vs p ≠ 0.1 Sample 1 X 19 N 100 Sample p 0.19 95% CI (0.113, 0.267) Z-Value 3.00 P-value 0.0027 What conclusion should be made at the a = 0.05 level? A) Because the P-value < a = 0.05, there is convincing evidence that the true proportion of players who win this game differs from 0.10. B) Because the P-value < a = 0.05, there is convincing evidence that the true proportion of players who win this game differs from 0.19. C) Because the P-value < a = 0.05, there is not convincing evidence that the true proportion of players who win this game differs from 0.10. D) Because the P-value < a = 0.05, there is not convincing evidence that the true proportion of players who win this game differs from 0.19.
carnival game is designed so that approximately 10% of players will win a large prize. If there is evidence that the percentage differs significantly from this target, then adjustments will be made to the game. To investigate, a random sample of 100 players is selected from the large population of all players. Of these players, 19 win a large prize. The question of interest is whether the data provide convincing evidence that the true proportion of players who win this game differs from 0.10. The computer output gives the results of a z-test for one proportion. Test and CI for One Proportion Test of p = 0.1 vs p ≠ 0.1 Sample 1 X 19 N 100 Sample p 0.19 95% CI (0.113, 0.267) Z-Value 3.00 P-value 0.0027 What conclusion should be made at the a = 0.05 level? A) Because the P-value < a = 0.05, there is convincing evidence that the true proportion of players who win this game differs from 0.10. B) Because the P-value < a = 0.05, there is convincing evidence that the true proportion of players who win this game differs from 0.19. C) Because the P-value < a = 0.05, there is not convincing evidence that the true proportion of players who win this game differs from 0.10. D) Because the P-value < a = 0.05, there is not convincing evidence that the true proportion of players who win this game differs from 0.19.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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A carnival game is designed so that approximately 10% of players will win a large prize. If there is evidence that the percentage differs significantly from this target, then adjustments will be made to the game. To investigate, a random sample of 100 players is selected from the large population of all players. Of these players, 19 win a large prize. The question of interest is whether the data provide convincing evidence that the true proportion of players who win this game differs from 0.10. The computer output gives the results of a z-test for one proportion.
Test and CI for One Proportion
Test of p = 0.1 vs p ≠ 0.1
Sample 1 |
X 19 |
N 100 |
Sample p 0.19 |
95% CI (0.113, 0.267) |
Z-Value 3.00 |
P-value 0.0027 |
What conclusion should be made at the a = 0.05 level?
A) Because the P-value < a = 0.05, there is convincing evidence that the true proportion of players who win this game differs from 0.10.
B) Because the P-value < a = 0.05, there is convincing evidence that the true proportion of players who win this game differs from 0.19.
C) Because the P-value < a = 0.05, there is not convincing evidence that the true proportion of players who win this game differs from 0.10.
D) Because the P-value < a = 0.05, there is not convincing evidence that the true proportion of players who win this game differs from 0.19.
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