Carbon disulfide is prepared by heating sulfur and charcoal. The chemical equation is S2(g)+C(s)↽−−⇀CS2(g)?c=9.40 at 900 KS2(g)+C(s)↽−−⇀CS2(g)Kc=9.40 at 900 K How many grams of CS2(g)CS2(g) can be prepared by heating 10.7 mol S2(g)10.7 mol S2(g) with excess carbon in a 6.10 L6.10 L reaction vessel held at 900 K until equilibrium is attained?
Carbon disulfide is prepared by heating sulfur and charcoal. The chemical equation is S2(g)+C(s)↽−−⇀CS2(g)?c=9.40 at 900 KS2(g)+C(s)↽−−⇀CS2(g)Kc=9.40 at 900 K How many grams of CS2(g)CS2(g) can be prepared by heating 10.7 mol S2(g)10.7 mol S2(g) with excess carbon in a 6.10 L6.10 L reaction vessel held at 900 K until equilibrium is attained?
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Carbon disulfide is prepared by heating sulfur and charcoal. The chemical equation is
S2(g)+C(s)↽−−⇀CS2(g)?c=9.40 at 900 KS2(g)+C(s)↽−−⇀CS2(g)Kc=9.40 at 900 K
How many grams of CS2(g)CS2(g) can be prepared by heating 10.7 mol S2(g)10.7 mol S2(g) with excess carbon in a 6.10 L6.10 L reaction vessel held at 900 K until equilibrium is attained?
Expert Solution
Step 1
Given ->
S2(g) + C(s) -----> CS2(g) Kc = 9.40
Initial moles of S2 = 10.7 mole
Volume= 6.10 L
-> C(s) is present in excess .
T = 900 K
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