Carbon dioxide is reduced by hydrogen according to the equation CO₂ (g) + H₂ (g) → CO (g) H₂0 (g). One mole of CO₂ is reacted with one mole of H₂ at 825 K and it is found that, at equilibrium, 0.27 atm of CO is present. Determine the equilibrium constant, K, at 835 K.

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Carbon dioxide is reduced by hydrogen according to the equation CO2 (g) + H₂ (g) CO (g) +
H₂0 (g). One mole of CO₂ is reacted with one mole of H₂ at 825 K and it is found that, at
equilibrium, 0.27 atm of CO is present. Determine the equilibrium constant, K, at 835 K.
Transcribed Image Text:Carbon dioxide is reduced by hydrogen according to the equation CO2 (g) + H₂ (g) CO (g) + H₂0 (g). One mole of CO₂ is reacted with one mole of H₂ at 825 K and it is found that, at equilibrium, 0.27 atm of CO is present. Determine the equilibrium constant, K, at 835 K.
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