Carbon-14 has a half-life of 5730 years. A sample of wood has been recovered by an archaeologist. The sample is sent to a laboratory, where it is determined that the activity of the sample is 0.144 Bq/g. By comparing this activity with the activity of living organic matter, 0.230 Bq/g, the scientist determines how old the wood sample is, or more precisely, when the tree that the sample came from died. How old is the sample of wood? O 2630 years O 2940 years O 4250 years O 4590 years O 3870 years o o o

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### Determining the Age of a Wooden Artifact Using Carbon-14 Dating

**Carbon-14 has a half-life of 5730 years. A sample of wood has been recovered by an archaeologist. The sample is sent to a laboratory, where it is determined that the activity of the sample is 0.144 Bq/g. By comparing this activity with the activity of living organic matter, 0.230 Bq/g, the scientist determines how old the wood sample is, or more precisely, when the tree that the sample came from died. How old is the sample of wood?**

#### Possible Answers:
- 2630 years
- 2940 years
- 4250 years
- 4590 years
- 3870 years

### Explanation:
To find the age of the wood sample, we use the formula for carbon dating, which is based on the exponential decay of Carbon-14. The formula is:

\[ N(t) = N_0 \cdot ( \frac{1}{2} )^{t/T} \]

Where:
- \( N(t) \) is the current activity (0.144 Bq/g).
- \( N_0 \) is the initial activity (0.230 Bq/g).
- \( t \) is the time elapsed.
- \( T \) is the half-life of Carbon-14 (5730 years).

Rearranging to solve for \( t \), we get:

\[ t = T \cdot \left( \frac{\log (N(t)/N_0)}{\log (1/2)} \right) \]

Applying the values:

\[ t = 5730 \cdot \left( \frac{\log (0.144/0.230)}{\log (1/2)} \right) \]

Calculating the logarithms:

\[ t = 5730 \cdot \left( \frac{\log (0.626)}{\log (0.5)} \right) \]
\[ t = 5730 \cdot \left( \frac{-0.204}{-0.301} \right) \]
\[ t = 5730 \cdot 0.678 \]

So:

\[ t \approx 3885.54 \]

The closest answer:

- **3870 years**

Remember to always cross-check your calculations and verify against provided options to ensure accuracy.
Transcribed Image Text:### Determining the Age of a Wooden Artifact Using Carbon-14 Dating **Carbon-14 has a half-life of 5730 years. A sample of wood has been recovered by an archaeologist. The sample is sent to a laboratory, where it is determined that the activity of the sample is 0.144 Bq/g. By comparing this activity with the activity of living organic matter, 0.230 Bq/g, the scientist determines how old the wood sample is, or more precisely, when the tree that the sample came from died. How old is the sample of wood?** #### Possible Answers: - 2630 years - 2940 years - 4250 years - 4590 years - 3870 years ### Explanation: To find the age of the wood sample, we use the formula for carbon dating, which is based on the exponential decay of Carbon-14. The formula is: \[ N(t) = N_0 \cdot ( \frac{1}{2} )^{t/T} \] Where: - \( N(t) \) is the current activity (0.144 Bq/g). - \( N_0 \) is the initial activity (0.230 Bq/g). - \( t \) is the time elapsed. - \( T \) is the half-life of Carbon-14 (5730 years). Rearranging to solve for \( t \), we get: \[ t = T \cdot \left( \frac{\log (N(t)/N_0)}{\log (1/2)} \right) \] Applying the values: \[ t = 5730 \cdot \left( \frac{\log (0.144/0.230)}{\log (1/2)} \right) \] Calculating the logarithms: \[ t = 5730 \cdot \left( \frac{\log (0.626)}{\log (0.5)} \right) \] \[ t = 5730 \cdot \left( \frac{-0.204}{-0.301} \right) \] \[ t = 5730 \cdot 0.678 \] So: \[ t \approx 3885.54 \] The closest answer: - **3870 years** Remember to always cross-check your calculations and verify against provided options to ensure accuracy.
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