Carbon-14 (14C) is a radioactive isotope of carbon with a half-life of 5730 years—meaning that half of the 14C in a sample decays into 14N during that time. Suppose a scientist analyzes a sample of ancient plant material from a bog and finds that it contains 1/8th as much 14C as when it formed. Roughly how old is the sample? _____ years
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Carbon-14 (14C) is a radioactive isotope of carbon with a half-life of 5730 years—meaning that half of the 14C in a sample decays into 14N during that time. Suppose a scientist analyzes a sample of ancient plant material from a bog and finds that it contains 1/8th as much 14C as when it formed. Roughly how old is the sample? _____ years
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- A radioactive element has a half-life of 3 days. The initial amount of that element is 1024 grams. How many grams of that element are left 12 days later? Write down your answer as an integer value (no decimals) and do not write the unit.Part 2: Rubidium-Strontium dating A geologist finds an old rock and wants to determine its age using rubidium-strontium dating. This is possible because 87Rb, which has a half-life of 4.75x1010 y, undergoes ß decay and becomes 87 Sr. The geologist determines that the ratio of 87 Sr to 87Rb is 0.136. Assuming there was no 87 Sr in the rock when it was formed, determine the age of the rock. age of rock =Radioactive tadium has half life of approx 1,599 years. This initial quantity is 19 grams. How much remains after 950 years? Round to two decimal) ….g
- Part 1: Carbon dating An archaeologist finds some ancient jewelry made from bone. The jewelry has a carbon mass of 387 g (HINT: Assume all the carbon is 12C and determine the number of atoms, 12C has a molar mass of 12 g/mol) and careful measurements show that the remaining 14C has a current decay rate of 20 decays/s. Determine the age of the bone (and presumably the jewelry). The ratio of 14C to 12C when the animal died was 1.25x10-12 & the half-life of 14C is 5730 y. Additionally, 1 mol = 6.022×1023 particles, 1 y = 365.25 days, & 1 day = 24 h. age of bone = Part 2: Rubidium-Strontium dating A geologist finds an old rock and wants to determine its age using rubidium-strontium dating. This is possible because 87Rb, which has a half-life of 4.75×1010 y, undergoes - decay and becomes 87Sr. The geologist determines that the ratio of 87 Sr to 87Rb is 0.033. Assuming there was no 87Sr in the rock when it was formed, determine the age of the rock. age of rock =The half-life of a radioactive isotope is 6.02 hours. 25.0 Grams of this isotope is needed for an experiment. How many grams of the isotope must be ordered if 48 hours pass between the time the isotope is ordered and the start of the experiment?The isotope ¹C has a half-life of 5730 years. What percent (N/No) of the ¹4C in a buried animal 14 bone will remain after 45,000 years?
- His case. ewent 5. A radioactive isotope, Selenium, used in the creation of medical images of the pancreas, has a half-life of 119.77 days. If 100 milligrams are given to a patient, how many milligrams are left after 20 days?A rock contains the radioactive isotope ? − 40 that decays with a half-life of 1.3 ??????? ????? and the radioactive isotope ?? − 87 that decays with a half-life of 48.6 ??????? ?????. The rock is 100 ??????? ????? old. The rock currently has 1000 times as many ?? − 87 atoms as there are ? − 40 atoms. (That is, ??? = 1000 × ??.) When the rock first formed it had ? times as many ?? − 87 atoms as ? − 40 atoms. (That is, ???,0 = ? × ??,0.) What is the value of ??In order to determine its rate of decay, 1 gram of an unknown radioactive isotope was placed in a container. The amount remaining was measured at 1-minute intervals and recorded in the table below. Time (in minutes) Grams remaining 0 1.000 1 0.956 2 0.914 3 0.874 4 0.835 5 0.799 Find an exponential model for the data with variable M corresponding to remaining mass (in grams) and t corresponding to time (in minutes). a) M = 1 × 95.600^t b) M = 0.956 x 1^tc) M =1 x 0.956^td) M = 95.600 x 1^t