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capacitor with parallel plates, of area A and separation 2a, is connected to a potential difference ∆V. Then a conductive metal plate of area is introduced A / 2 and thickness a up to the middle of the capacitor (red in the figure). Finally it is introduced an insulating material of dielectric constant κ in the second half (blue in the figure), with equal area and thickness as conductive material. Find The capacity and accumulated energy when the capacitor is empty.

capacitor with parallel plates, of area A and separation 2a, is connected to a potential difference ∆V. Then a conductive metal plate of area is introduced A / 2 and thickness a up to the middle of the capacitor (red in the figure). Finally it is introduced an insulating material of dielectric constant κ in the second half (blue in the figure), with equal area and thickness as conductive material. Find The capacity and accumulated energy when the capacitor is empty.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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A capacitor with parallel plates, of area A and separation 2a, is connected to a potential difference ∆V. Then a conductive metal plate of area is introduced A / 2 and thickness a up to the middle of the capacitor (red in the figure). Finally it is introduced an insulating material of dielectric constant κ in the second half (blue in the figure), with equal area and thickness as conductive material. Find The capacity and accumulated energy when the capacitor is empty.

Fa/2 Δν Fa/2 FIGURE 1 - Condensador problema 1.
Transcribed Image Text:Fa/2 Δν Fa/2 FIGURE 1 - Condensador problema 1.
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