I need the answer as soon as possible i llı.Tinعبیر+L3Path: pQuestion 17Not yet answeredMarked out of 10,00P Flag questionVoltage ratingCapacitance10 V50 V100 VTotal4 pF12 pF20 pF911133312168361014731Total314128100in a lab, there are 100 capacitors of three valuesand three voltage ratings as shown in Table 2.1. Letevent A be drawing 12 pF capacitor and event B bedrawing a 50 V capacitor. Determine: (a) P(A) andP(B). (b) P(AB), (c) P(A/B), (d) P(B/A).(10 M)ParagraphB III

We have to answer the basic probability questions depends on the given table.

Answered: Capacitance 4 pF 12 pF 20 pF 10 V 50 V…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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How wellmaterials conduct heat matters when designing houses, forexample. Conductivity is measured in terms of watts of heatpower transmitted per square meter of surface per degree Celsius of temperature difference on the two sides of the material.The National Institute of Standards and Technology (NIST)provides data on properties of materials. Here are 9 NISTmeasurements of the heat conductivity of a particular type offibrous-glass board: 0.0339 0.0337 0.0334 0.0334 0.03330.0333 0.0333 0.0332 0.0330 (a) We can consider this an SRS of all specimens of fibrousglass board of this type. Make a stemplot. Is there any sign ofmajor deviation from Normality? (b) Give a 95% confidence interval for the mean conductivity. (c) Is there significant evidence at the 5% level that themean conductivity of this type of fibrous-glass board is not0.0330?
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SOLVE STEP BY STEP IN DIGITAL FORMAT 1.- The following data refer to the weight loss of certain mechanical parts (milligrams) due to friction when three different lubricants were used under controlled conditions: lubric. A 12.2,11.8,13.1,11.0, 3.9, 4.1,10.3, 8.4 lubric. B 10.9, 5.7,13.5, 9.4,11.4,15.7,10.8,14.0 lubric. C 12.7,13.6,11.7,18.3,14.3, 22.8, 20.4,12.2 Proof, if there is a difference between the lubricants in the loss of weight due to friction of certain mechanical parts.
Fill the chi square for Cross 1 and Cross 2 from the following data in the attached image: Cross 1: Phenotypes Ratio Observed Expected (O-E)2/E Totals X2 = Cross 2: Phenotypes Ratio Observed Expected (O-E)2/E Totals X2 =
Weotherwise is a magazine published by the American Mctcorological Socicty. One issue gives a rating system used to classify Nor'easter storms that froquently hit New England and can cause much damage near the occan. A severe storm has an average peak wave height of g = 16.4 feet for waves hitting the shore. Suppose that a Nor'easter is in progress at the severe storm class rating. Peak wave heights are usually measured from land (using binoculars) oft tixed cament plers. Suppose that a reading of 35 waves showed an zverage wave height of x- 17.3 foet. Pravlous studies of severe storms indilcate that o- 3.5 foet. Doas this information suggost that the storm is (perhaps tamporarily) Increasing above the severe rating? Usa a - 0.01. (a) What is the levcl of significance? .01 State the null and altarnate hypothesas. O Ho: H - 16.4 t; H 10.4 t; H: - 16.4 t O Ho: H 10.4 ft; H: - 10.4 ft O Ho: H - 10.1 ft; H:+ 10.1 t * Ho: H = 10.1 ft; H:> 16.1 ft (b) What sampling distrihutian will you…
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One operation of a mill is to cut pieces of steel into parts that will later be used as the frame for front seats in an automobile. The steel is cut with a diamond saw and requires the resulting parts to be within 10.005 inch of the length specified by the automobile company. Data are collected from a sample of 50 steel parts and are shown in the following table. The measurement reported is the difference in inches between the actual length of the steel part, as measured by a laser measurement device, and the specified length of the steel part. For example, the first value, -0.003, represents a steel part that is 0.003 inch shorter than the specified length. Complete parts a through c Click the icon to view the data table. a. Construct a frequency distribution Difference in Length -0.005 but less than -0.003: -0.003but less than -0.001 -0.001but less than 0.001 0.001but less than 0.003 0.003but less than 0.005 Frequency Difference Between Actual and Specified Lengths 0.002 0 -0.003…
A manufacturing company produces electric insulators. You define the variable of interest as the strength of the insulators. If the insulators break when in use, a short circuit is likely. To test the strength of the insulators, you carry out destructive testing to determine how much force is required to break the insulators. You measure force by observing how many pounds are applied to the insulator before it breaks. The accompanying data represent the amount of force required to break a sample of 30 insulators. 1,865 1,706 1,698 1,619 1,609 1,779 1,570 1,693 1,581 1,668 1,898 1,755 1,729 1,698 1,704 1,780 1,883 1,771 1,799 1,867 1,812 1,713 1,754 1,793 1,823 1,791 1,668 1,815 1,677 1,707 Construct a 90% confidence interval for the population mean force. ___ ≤μ≤ ___
A manufacturing company produces electric insulators. You define the variable of interest as the strength of the insulators. If the insulators break when in use, a short circuit is likely. To test the strength of the insulators, you carry out destructive testing to determine how much force is required to break the insulators. You measure force by observing how many pounds are applied to the insulator before it breaks. The accompanying data represent the amount of force required to break a sample of 30 insulators. Complete parts (a) through (c) below. Click the icon to view the data. a. Construct a 95% confidence interval for the population mean force. ο sus Π (Round to the nearest integer as needed.)
A manufacturing company produces electric insulators. You define the variable of interest as the strength of the insulators. If the insulators break when in use, a short circuit is likely. To test the strength of the insulators, you carry out destructive testing to determine how much force is required to break the insulators. You measure force by observing how many pounds are applied to the insulator before it breaks. The accompanying data represent the amount of force required to break a sample of 30 insulators. a. Construct a 99% confidence interval for the population mean force.

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