(CANNOT USE ARRAY AND ONLY CAN USE WHILE LOOPS) Write a C++ program that asks the user to enter a positive integer n and then that reads n user input integers and finally prints the message The numbers you entered are in  increasing order if they are in increasing order or the message The numbers you entered  are NOT in increasing order if they are not. See the remark below. Remark:- Remember given the numbers a1, a2, a3, ..., an; we say they are in increasing order  if a1 ≤ a2 ≤ a3 ≤ .... ≤ an. Moreover remember that if you have only one number from the  user input then the number automatically is in increasing order.

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(CANNOT USE ARRAY AND ONLY CAN USE WHILE LOOPS)

Write a C++ program that asks the user to enter a positive integer n and then that reads n
user input integers and finally prints the message The numbers you entered are in 
increasing order if they are in increasing order or the message The numbers you entered 
are NOT in increasing order if they are not. See the remark below.
Remark:- Remember given the numbers a1, a2, a3, ..., an; we say they are in increasing order 
if a1 ≤ a2 ≤ a3 ≤ .... ≤ an. Moreover remember that if you have only one number from the 
user input then the number automatically is in increasing order.

Expert Solution
Step 1

#include<iostream>
using namespace std;
int main(){
 int n,t1,t2,i=0;
 // Assume the list is in Strictly increasing by default
 bool result=true;
 // read all the values 
 cout<<"Enter a Positive Number : ";
 cin>>n;
 cout<<"Enter "<<n<<" Elements : ";
 while(i<n){
  cin>>t2;
  if(i==0)
   t1=t2;
  // If the previous number is greater than first
  // then list is in decreasing order
  if(t1>t2){
   result=false;
     }
     t1=t2;
     i++;
 }
 // print the result   
 if(!result)
  cout<<"The Numbers you entered are not in increasing order ";
 else
  cout<<"The Numbers you entered are in increasing order ";
}

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