show solution and all steps. thermo 2. first solve with cold air standard, then solve without cold air standard. label part 1 and part 2 9.6 A four-cylinder, four-stroke internal combustion engineoperates at 2800 RPM. The processes within each cylinderare modeled as an air-standard Otto cycle with a pressure of14.7 lbf/in.², a temperature of 80°F, and a volume of 0.0196 ft³at the beginning of compression. The compression ratio is10, and maximum pressure in the cycle is 1080 lbf/in.²Determine, using a cold air-standard analysis with k = 1.4,the power developed by the engine, in horsepower, and themean effective pressure, in lbf/in.²

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Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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show solution and all steps. thermo 2. first solve with cold air standard, then solve without cold air standard. label part 1 and part 2

9.6 A four-cylinder, four-stroke internal combustion engine
operates at 2800 RPM. The processes within each cylinder
are modeled as an air-standard Otto cycle with a pressure of
14.7 lbf/in.², a temperature of 80°F, and a volume of 0.0196 ft³
at the beginning of compression. The compression ratio is
10, and maximum pressure in the cycle is 1080 lbf/in.²
Determine, using a cold air-standard analysis with k = 1.4,
the power developed by the engine, in horsepower, and the
mean effective pressure, in lbf/in.²

Expert Solution

Step 1: Write the given data with suitable variables-

$Speed comma space N equals space 2800 space rpm P subscript 1 equals 14.7 space lbf divided by in squared space equals 101352.932 space Pa T subscript 1 equals 80 degree straight F space equals space 299.8167 space straight K V subscript 1 space equals space 0.0196 space ft cubed space equals space 0.00056 space straight m cubed Compression space Ratio comma space CR space equals 10 Maximum space pressure space in space the space cycle comma space P subscript 3 equals 1080 space lbf divided by in squared space equals 7446337.85 space Pa straight k space equals space 1.4$