Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
Related questions
Question
Can you show the work for exponents, How did (x^3-x)/sqrt(x) = to x^3-1/3 - X^1-1/2 = x^5/2 - x^1/2
![Solutions:
1. Find the equation of the tangent line to the function f(x)
x = 25.
I
Let f(x) = 2³-²
At x = 25, f(25)
5
Then f'(x) = -¹-1-¹-2/2 - 11/2
2
f'(25)
x²³²x²¹ ²² = x/2 - ¹/2
I
m =
312.4
= I
25³ - 25
√25
25³/2
11/12.
5
==x³/2
15600
5
-25-1/2
-
5
2
3120, and
125
- I
3124
1 1 625 1
25 2 10 10
at
Using the Slope-Point Formula to get the equation of the tangent line,
we obtain y- 3120 = 312.4(x - 25), or y = 312.4x 4690](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff498376d-e0fb-42fd-89a5-37b7d45255f7%2Fc707e961-18ad-4d51-8116-3f966736856c%2Fy1p0wun_processed.png&w=3840&q=75)
Transcribed Image Text:Solutions:
1. Find the equation of the tangent line to the function f(x)
x = 25.
I
Let f(x) = 2³-²
At x = 25, f(25)
5
Then f'(x) = -¹-1-¹-2/2 - 11/2
2
f'(25)
x²³²x²¹ ²² = x/2 - ¹/2
I
m =
312.4
= I
25³ - 25
√25
25³/2
11/12.
5
==x³/2
15600
5
-25-1/2
-
5
2
3120, and
125
- I
3124
1 1 625 1
25 2 10 10
at
Using the Slope-Point Formula to get the equation of the tangent line,
we obtain y- 3120 = 312.4(x - 25), or y = 312.4x 4690
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