Can you resolve? 5-bit ADC, V=0.6V, Ve=1 Cycle 1 => MSB=1 SAR = 10000 VDAC = Vres21 = .5 Vin > VDAC SAR unchanged =10000 Cycle 2 SAR = 1100 0 VOAC = .5 +.25 = .75 Vn < VDAC SAR bit3 reset to 0 = 1000 Cycle 3 SAR = 1010 0 VDAC = .5 + .125 = .625 Vn < VDAc SAR bit2 reset to 0 = 10000 • Cycle 4 SAR = 10010 VOẠC = .5+.0625=.5625 Vn > VDAC SAR unchanged 100 10 • Cycle 5 SAR = 100 11 ENTSND INSERUM VOAC = .5+.0625+.03125= 59375 Bit 4 Voltage .5 .125 .0625 .03125

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Digital Integrated Circuit Design

Digital IC design is a procedural interaction that involves converting determinations and highlights into computerized blocks, which are then further transformed into basic circuits. A significant number of the imperatives related with advanced IC plan come from the foundry cycle and innovative restrictions.