Can you resolve? 5-bit ADC, V=0.6V, Ve=1 Cycle 1 => MSB=1 SAR = 10000 VDAC = Vres21 = .5 Vin > VDAC SAR unchanged =10000 Cycle 2 SAR = 1100 0 VOAC = .5 +.25 = .75 Vn < VDAC SAR bit3 reset to 0 = 1000 Cycle 3 SAR = 1010 0 VDAC = .5 + .125 = .625 Vn < VDAc SAR bit2 reset to 0 = 10000 • Cycle 4 SAR = 10010 VOẠC = .5+.0625=.5625 Vn > VDAC SAR unchanged 100 10 • Cycle 5 SAR = 100 11 ENTSND INSERUM VOAC = .5+.0625+.03125= 59375 Bit 4 Voltage .5 .125 .0625 .03125

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Can you resolve?
5-bit ADC, Vn=0.6V, Vret=1
Example (2)
Cycle 1 => MSB=1
SAR = 10000
VDAC = Vres/21 = .5
Vin > VDAC SAR unchanged = 1000
• Cycle 2
SAR = 1100 0
VOAC = .5 +.25 = .75
Vn < VDAC SAR bit3 reset to 0 = 1000
• Cycle 3
SAR = 10100
VOAC = .5 + .125 = .625
Vn < VDAC
SAR bit2 reset
10000
• Cycle 4
SAR = 10010
VOAC = .5+.0625=.5625
Vn > VDAC
nchanged = 1 0010
• Cycle 5
SAR = 100 11
VDAC = .5+.0625+.03125= ,59375
DENTS D INSERUMAT
Bit
4
Voltage
.5
.0625
.03125
Transcribed Image Text:Can you resolve? 5-bit ADC, Vn=0.6V, Vret=1 Example (2) Cycle 1 => MSB=1 SAR = 10000 VDAC = Vres/21 = .5 Vin > VDAC SAR unchanged = 1000 • Cycle 2 SAR = 1100 0 VOAC = .5 +.25 = .75 Vn < VDAC SAR bit3 reset to 0 = 1000 • Cycle 3 SAR = 10100 VOAC = .5 + .125 = .625 Vn < VDAC SAR bit2 reset 10000 • Cycle 4 SAR = 10010 VOAC = .5+.0625=.5625 Vn > VDAC nchanged = 1 0010 • Cycle 5 SAR = 100 11 VDAC = .5+.0625+.03125= ,59375 DENTS D INSERUMAT Bit 4 Voltage .5 .0625 .03125
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