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Given Ao = 4A, R₁ = R3 = 1, N and R₂ = 2, N, compute the current 1₂ A₂ ↑ R₁² R₂² R₂3 Iz √, A O, A O-16, A O 2, A К

Given Ao = 4A, R₁ = R3 = 1, N and R₂ = 2, N, compute the current 1₂ A₂ ↑ R₁² R₂² R₂3 Iz √, A O, A O-16, A O 2, A К

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Given Ao = 4 A, R₁ = R3 = 1, 2 and R₂ A₂ ↑ R₁² R₂² R₂3 YI₂ √, A O, A O-, A O2, A = 2, 2, compute the current I2
Transcribed Image Text:Given Ao = 4 A, R₁ = R3 = 1, 2 and R₂ A₂ ↑ R₁² R₂² R₂3 YI₂ √, A O, A O-, A O2, A = 2, 2, compute the current I2
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can you repeat it with more detail? why in the first current division rule is R1 in the numerator and in the 2nd how and why did we use I2+i3 instead of A0? and also why was R3 in the numerator? please resolve in more details

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