Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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can you please explain the answer by solving this question again?
![1
~18165
10. Consider the function: f(x) = 2¹-26. Find all maxima, minima and
points of inflection for this function. Plot the function.
6
f(x).
Of
R
0096
Rf = (-∞, max+ f(x)]
The function has
inflection points at.
X = ± √√ 45
+² (1²75) = (23) ³² (1-62)
0
1.096
14.
20
3
5
3
"f'(x) = 4x² - 6x² = x³² (4-62²)
f=o= x=0
>0
-x
and stays positive around
√75
ƒ' (~√ ²5) = − ( 2 ) ² (4-612) <0
५०
aroud.
.8165
122² - 30x4
We need to check x=0
for max or
min
and x=02
x = ± √75 for in
and starp negative.
-√2/5
x
N
o² 4-6x² = 0 = x = ± √√√ 7/₂
= 6x² (2-5x²) = 0
11
At x = 0
fill (
x=
(= ± √√7/3
x*(1-x²)
O
fe1=0 at x=0
f" (x) < 0 at x = 18169
f"(x) <0 at x==18165
continue.
we
・flecter points.
if se zo
2x=+√√7/5
x=+1
'(x) = 24x - 120x²
+.8165
=+6325
both are
maxima
taking
dercontives
f (x) = 24-240x
But f" (0) = 2470
So we have an wen.
derivative as the first
derivature and it is positie.
поп-зего
x=0 is a minimum.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fba7d748a-252c-474b-931e-93acb5db0c03%2F83347d06-1d57-479f-87ad-5a1b9bba078e%2Fmlf2nx_processed.png&w=3840&q=75)
Transcribed Image Text:1
~18165
10. Consider the function: f(x) = 2¹-26. Find all maxima, minima and
points of inflection for this function. Plot the function.
6
f(x).
Of
R
0096
Rf = (-∞, max+ f(x)]
The function has
inflection points at.
X = ± √√ 45
+² (1²75) = (23) ³² (1-62)
0
1.096
14.
20
3
5
3
"f'(x) = 4x² - 6x² = x³² (4-62²)
f=o= x=0
>0
-x
and stays positive around
√75
ƒ' (~√ ²5) = − ( 2 ) ² (4-612) <0
५०
aroud.
.8165
122² - 30x4
We need to check x=0
for max or
min
and x=02
x = ± √75 for in
and starp negative.
-√2/5
x
N
o² 4-6x² = 0 = x = ± √√√ 7/₂
= 6x² (2-5x²) = 0
11
At x = 0
fill (
x=
(= ± √√7/3
x*(1-x²)
O
fe1=0 at x=0
f" (x) < 0 at x = 18169
f"(x) <0 at x==18165
continue.
we
・flecter points.
if se zo
2x=+√√7/5
x=+1
'(x) = 24x - 120x²
+.8165
=+6325
both are
maxima
taking
dercontives
f (x) = 24-240x
But f" (0) = 2470
So we have an wen.
derivative as the first
derivature and it is positie.
поп-зего
x=0 is a minimum.
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