can you please convert this python code into java? Python code is as shown below: # recursive function def row_puzzle_rec(row, pos, visited): # if the element at the current position is o we have reached our goal if row[pos] == 0: possible = True else: # make a copy of the visited array visited = visited[:] # if the element at the current position has been already visited then it's a loop. # as then its not possible to reach the last element, set possible to False if visited[pos]: possible = False else: #set visitied for the element as True visited[pos] = True possible = False # if its possible to move left then recurse in the left direction if pos - row[pos]>o and row_puzzle_rec(row, pos - row[pos], visited): # return immediately if the goal is reached return True # if its possible to move right then recurse in the right direction if pos + row[pos] < len(row) and row_puzzle_rec(row, pos + row[pos], visited): # return immediately if the goal is reached. return True return possible def row_puzzle(row): #visited array will be used to check if a particular element was visited # initialize the array to False visited = [False for item in range(len(row))] # second argument is the token position initialized to o return row_puzzle_rec(row, o, visited) possible = row_puzzle([2, 4, 5, 3, 1, 3, 1, 4, ol) print(possible) possible = row_puzzle([1, 3, 2, 1, 3, 4, 0)) print(possible)
can you please convert this python code into java? Python code is as shown below: # recursive function def row_puzzle_rec(row, pos, visited): # if the element at the current position is o we have reached our goal if row[pos] == 0: possible = True else: # make a copy of the visited array visited = visited[:] # if the element at the current position has been already visited then it's a loop. # as then its not possible to reach the last element, set possible to False if visited[pos]: possible = False else: #set visitied for the element as True visited[pos] = True possible = False # if its possible to move left then recurse in the left direction if pos - row[pos]>o and row_puzzle_rec(row, pos - row[pos], visited): # return immediately if the goal is reached return True # if its possible to move right then recurse in the right direction if pos + row[pos] < len(row) and row_puzzle_rec(row, pos + row[pos], visited): # return immediately if the goal is reached. return True return possible def row_puzzle(row): #visited array will be used to check if a particular element was visited # initialize the array to False visited = [False for item in range(len(row))] # second argument is the token position initialized to o return row_puzzle_rec(row, o, visited) possible = row_puzzle([2, 4, 5, 3, 1, 3, 1, 4, ol) print(possible) possible = row_puzzle([1, 3, 2, 1, 3, 4, 0)) print(possible)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
Related questions
Question
Convert please asap.
![can you please convert this python code into java?
Python code is as shown below:
# recursive function
def row_puzzle_rec(row, pos, visited):
# if the element at the current position is o we have reached
our goal
if row[pos] == 0:
possible = True
else:
# make a copy of the visited array
visited visited[:]
# if the element at the current position has been already
visited then it's a loop.
# as then its not possible to reach the last element, set
possible to False
if visited[pos]:
possible = False
else:
#set visitied for the element as True
visited[pos] = True
possible = False
# if its possible to move left then recurse in the left
direction
if pos - row[pos]>o and row_puzzle_rec(row, pos -
row[pos], visited):
# return immediately if the goal is reached
return True
# if its possible to move right then recurse in the right
direction
if pos + row[pos] < len(row) and row_puzzle_rec(row, pos +
row[pos], visited):
# return immediately if the goal is reached.
return True
return possible
def row_puzzle(row):
#visited array will be used to check if a particular element was
visited
# initialize the array to False
visited = [False for item in range(len(row))]
#second argument is the token position initialized to o
return row_puzzle_rec(row, o, visited)
possible = row_puzzle([2, 4, 5, 3, 1, 3, 1, 4, ol)
print(possible)
possible = row_puzzle([1, 3, 2, 1, 3, 4, 0])
print(possible)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fff8bc427-4dd5-458f-a0de-0d1350ec468a%2Fe825f587-8664-4008-a71f-b94236869912%2F04q7r34_processed.jpeg&w=3840&q=75)
Transcribed Image Text:can you please convert this python code into java?
Python code is as shown below:
# recursive function
def row_puzzle_rec(row, pos, visited):
# if the element at the current position is o we have reached
our goal
if row[pos] == 0:
possible = True
else:
# make a copy of the visited array
visited visited[:]
# if the element at the current position has been already
visited then it's a loop.
# as then its not possible to reach the last element, set
possible to False
if visited[pos]:
possible = False
else:
#set visitied for the element as True
visited[pos] = True
possible = False
# if its possible to move left then recurse in the left
direction
if pos - row[pos]>o and row_puzzle_rec(row, pos -
row[pos], visited):
# return immediately if the goal is reached
return True
# if its possible to move right then recurse in the right
direction
if pos + row[pos] < len(row) and row_puzzle_rec(row, pos +
row[pos], visited):
# return immediately if the goal is reached.
return True
return possible
def row_puzzle(row):
#visited array will be used to check if a particular element was
visited
# initialize the array to False
visited = [False for item in range(len(row))]
#second argument is the token position initialized to o
return row_puzzle_rec(row, o, visited)
possible = row_puzzle([2, 4, 5, 3, 1, 3, 1, 4, ol)
print(possible)
possible = row_puzzle([1, 3, 2, 1, 3, 4, 0])
print(possible)
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 3 steps with 1 images
Recommended textbooks for you
Computer Networking: A Top-Down Approach (7th Edi…
Computer Engineering
ISBN:
9780133594140
Author:
James Kurose, Keith Ross
Publisher:
PEARSON
Computer Organization and Design MIPS Edition, Fi…
Computer Engineering
ISBN:
9780124077263
Author:
David A. Patterson, John L. Hennessy
Publisher:
Elsevier Science
Network+ Guide to Networks (MindTap Course List)
Computer Engineering
ISBN:
9781337569330
Author:
Jill West, Tamara Dean, Jean Andrews
Publisher:
Cengage Learning
Computer Networking: A Top-Down Approach (7th Edi…
Computer Engineering
ISBN:
9780133594140
Author:
James Kurose, Keith Ross
Publisher:
PEARSON
Computer Organization and Design MIPS Edition, Fi…
Computer Engineering
ISBN:
9780124077263
Author:
David A. Patterson, John L. Hennessy
Publisher:
Elsevier Science
Network+ Guide to Networks (MindTap Course List)
Computer Engineering
ISBN:
9781337569330
Author:
Jill West, Tamara Dean, Jean Andrews
Publisher:
Cengage Learning
Concepts of Database Management
Computer Engineering
ISBN:
9781337093422
Author:
Joy L. Starks, Philip J. Pratt, Mary Z. Last
Publisher:
Cengage Learning
Prelude to Programming
Computer Engineering
ISBN:
9780133750423
Author:
VENIT, Stewart
Publisher:
Pearson Education
Sc Business Data Communications and Networking, T…
Computer Engineering
ISBN:
9781119368830
Author:
FITZGERALD
Publisher:
WILEY