Can you help me with the full solution since it is shortcut, especially on the value of -2 sqrt of 2/2 on how it was obtained At the point (V2, V2,), t=" and the unit tangent vector isTT1Ti + 2j + k/52i + /2j + k).Using the direction numbers a =/2, b = /2, and c = 1,and the point you can obtain (x1, Y1, Z1) = (v2, v2,)the following parametric equations (given with parameters)x = x, + as = /2 – /2sy = y, + bs= 2 + /2sz = Z, + cs =TT+ s4 The tangent line to a curve at a point is the line thatpasses through the point and is parallel to the unit tangentvectorExample1. Find T(t) and then find a set of parametric equations for the tangentline to the helix givenr(t) = 2cos ti + 2sin tj + tkat the point (V2, vZ,"),Solution:The derivative of r(t) is r'(t) = –2sin t i + 2cos tj + k, whichimplies that r (t) || = /4 sin? t + 4 cos² t + 1 = /5.Therefore, the unit tangent vector isr (t)||r (1)||Tt)

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Answered: Can you help me with the full solution…

Can you help me with the full solution since it is shortcut, especially on the value of -2 sqrt of 2/2 on how it was obtained

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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