Can you help me with part 1.9 part A because I am really struggling with state diagrams and this problem is a state diagram. Could you please show something visual like drawing a circle with the correct answer for this problem because I am struggling. i DON'T KNOW WHAT THEORM 1.47 MEAN SO. iHAVE PROVIDED IT BECAUSE YOU CAN HELP ME UNDERSTAND IT BETTER.To answer 1.9 you will need excersie 1.6g and 1.6i which will be provided and theorem 1.47 which is provided in the photo. i ONLY NEED HELP IS WITH 1.9 PART A.question for 1.9:1.9 Use the construction in the proof of Theorem 1.47 to give the state diagrams of NFAs recognizing the concatenation of the languages described ina. Exercises 1.6g and 1.6i. Exercises 1.6g and 1.6i1.6 Give state diagrams of DFAs recognizing the following languages. In all parts, the alphabet is {0,1}.g. {w| the length of w is at most 5}i. {w| every odd position of w is a 1} THEOREM 1.47The class of regular languages is closed under the concatenation operation.PROOF IDEA We have regular languages A₁ and A2 and want to prove thatA₁ A2 is regular. The idea is to take two NFAs, N₁ and N₂ for A₁ and A2, andcombine them into a new NFA N as we did for the case of union, but this timein a different way, as shown in Figure 1.48.Assign N's start state to be the start state of N₁. The accept states of №₁ haveadditional e arrows that nondeterministically allow branching to N₂ wheneverN₁ is in an accept state, signifying that it has found an initial piece of the inputthat constitutes a string in A₁. The accept states of N are the accept states of N₂only. Therefore, it accepts when the input can be split into yo parts, the firstaccepted by N₁ and the second by N2. We can think of N as nondeterministicallyguessing where to make the split.yright 2012 Cengage Learning. All Rights Reserved. May not be copied, scanned, or duplicated, in whole or in part. Due to electronic rights, some third party content may be suppressed fromk and/or cChapter(s). Editorial review has deemed that any suppressed content does not materially affect the overall learning experience. Cengage Learning reserves the right to remove additicontent at any time if subsequent rights restrictions require itNN₁TO BRADONNOND DOORDNONG GAN TO DOOR nd go anOOO оо8E€€N₂1.2NONDETERMINISMO OO61

NFA stands for Non deterministic Finite Automata which is a type of automata that accepts the…

Answered: Can you help me with part 1.9 part A…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Can you help me with part 1.9 part A because I am really struggling with state diagrams and this problem is a state diagram. Could you please show something visual like drawing a circle with the correct answer for this problem because I am struggling. i DON'T KNOW WHAT THEORM 1.47 MEAN SO. iHAVE PROVIDED IT BECAUSE YOU CAN HELP ME UNDERSTAND IT BETTER.

To answer 1.9 you will need excersie 1.6g and 1.6i which will be provided and theorem 1.47 which is provided in the photo. i ONLY NEED HELP IS WITH 1.9 PART A.

question for 1.9:

1.9 Use the construction in the proof of Theorem 1.47 to give the state diagrams of NFAs recognizing the concatenation of the languages described in

a. Exercises 1.6g and 1.6i.

Exercises 1.6g and 1.6i

1.6 Give state diagrams of DFAs recognizing the following languages. In all parts, the alphabet is {0,1}.

g. {w| the length of w is at most 5}

i. {w| every odd position of w is a 1}

THEOREM 1.47
The class of regular languages is closed under the concatenation operation.
PROOF IDEA We have regular languages A₁ and A2 and want to prove that
A₁ A2 is regular. The idea is to take two NFAs, N₁ and N₂ for A₁ and A2, and
combine them into a new NFA N as we did for the case of union, but this time
in a different way, as shown in Figure 1.48.
Assign N's start state to be the start state of N₁. The accept states of №₁ have
additional e arrows that nondeterministically allow branching to N₂ whenever
N₁ is in an accept state, signifying that it has found an initial piece of the input
that constitutes a string in A₁. The accept states of N are the accept states of N₂
only. Therefore, it accepts when the input can be split into yo parts, the first
accepted by N₁ and the second by N2. We can think of N as nondeterministically
guessing where to make the split.
yright 2012 Cengage Learning. All Rights Reserved. May not be copied, scanned, or duplicated, in whole or in part. Due to electronic rights, some third party content may be suppressed from
k and/or cChapter(s). Editorial review has deemed that any suppressed content does not materially affect the overall learning experience. Cengage Learning reserves the right to remove additi
content at any time if subsequent rights restrictions require it
N
N₁
TO BRADONNOND DOORDNONG GAN TO DOOR nd go an
O
O
O о
о
8
E
€
€
N₂
1.2
NONDETERMINISM
O O
O
61

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