Can you help me solve these 3 questions using Statcrunch? please and thank you! Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim.  23) The health of employees is monitored by periodically weighing them in. A sample of 54 employees has a mean weight of 183.9 lb. Assuming that CJ is known to be 121.2 lb, use a 0.10 significance level to test the claim that the population mean of all such employees weights is less than 200 lb.

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ISBN:9781119256830
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Chapter1: Starting With Matlab
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Can you help me solve these 3 questions using Statcrunch? please and thank you!

Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. 
23) The health of employees is monitored by periodically weighing them in. A sample of 54 employees has a mean weight of 183.9 lb. Assuming that CJ is known to be 121.2 lb, use a 0.10 significance level to test the claim that the population mean of all such employees weights is less than 200 lb. 


MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. 
Do one of the following, as appropriate: (a) Find the critical value Za/2- (b) find the critical value ta/2- (c) state that 
neither the normal nor the t distribution applies. 


24) 99%; n = 17; CJ is unknown; population appears to be normally distributed
A) Za./2 = 2.583 B) Za/2 = 2.567 C) ta/2 = 2.898 D) ta./2 = 2.921 
Use the given degree of confidence and sample data to construct a confidence interval for the population mean 1-1· Assume 
that the population has a normal distribution. 


25) The football coach randomly selected ten players and timed how long each player took to perform a certain drill. The times (in minutes) were: 
7.0 10.8 9.5 8.0 11.5 
7.5 6.4 11.3 10.2 12.6 
Determine a 95% confidence interval for the mean time for all players (include a means plot for the data) 
A) 7.93 min< 1-1< 11.03 min 
C) 10.93 min< 1-1 < 8.03 min 
 
B) 8.03 min< 1-1 < 10.93 min 
D) 11.03 min< 1-1 < 7.93 min

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