8. Suppose that X and Y are means from two large (larger than 30) independent samples E(X)= 106; Var (X)= 16; E(Y)-98; Var(Y) =9. Based on the Central Limit Theorem, we can say that P(X-Y>10) is approximately: (A) 0.3446 (B) 0.2236 (C) 0.4681 (D) 0.3859 (E) 0.0228
8. Suppose that X and Y are means from two large (larger than 30) independent samples E(X)= 106; Var (X)= 16; E(Y)-98; Var(Y) =9. Based on the Central Limit Theorem, we can say that P(X-Y>10) is approximately: (A) 0.3446 (B) 0.2236 (C) 0.4681 (D) 0.3859 (E) 0.0228
MATLAB: An Introduction with Applications
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Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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please show the step by step solution and provide an explanation on why that is the right answer. Please do not skip steps.
![Answer is A
8. Suppose that X and Y are means from two large (larger than 30) independent samples
E(X)= 106; Var (X) = 16; E(Y) =98; Var(Y) = 9.
Based on the Central Limit Theorem, we can say that P(X-Y>10) is approximately:
(A) 0.3446
(B) 0.2236
(C) 0.4681
(D) 0.3859
(E) 0.0228](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3bf2a50d-4512-42df-9825-e6fb8f760832%2F6ae85205-570a-4d66-bff7-2e423d6afa59%2Fuc7je7_processed.png&w=3840&q=75)
Transcribed Image Text:Answer is A
8. Suppose that X and Y are means from two large (larger than 30) independent samples
E(X)= 106; Var (X) = 16; E(Y) =98; Var(Y) = 9.
Based on the Central Limit Theorem, we can say that P(X-Y>10) is approximately:
(A) 0.3446
(B) 0.2236
(C) 0.4681
(D) 0.3859
(E) 0.0228
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Can you explain why it is you added V(X-Y) = V(X) + V(Y) = 16 + 9 =25? What is the reasoning behind it? What if it was V(X+Y)? Would you then do the opposite and subtract
= V(X) - V(Y) = 16 - 9 = 7?
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