Can you explain this code? It is "Beautiful Pairs" Hackerrank question's solution. 15public class Solution {1617private static final int MAX_NUM = 100e; // max value of any number in array%3D1819public static void main(String[] args) {Scanner scan = new Scanner (System.in);2021int N = scan.nextInt();int [] bucketA = new int[MAX_NUM + 1];for (int i = 0; i < N; i++) {bucketA[scan.nextInt ()]++;2223242526int beautifu1Pairs = 0;%3Dfor (int i = 0; i < N; i++) {2728int num = scan.nextInt();29if (bucketA[num] > 0) {30bucketA[num]--;31beautifulPairs++;32}3334scan.close();3536/* Accounts for changing 1 element in B */37if (beautifulPairs == N) {38beautifulPairs--;} else {3940beautifulPairs++;4142System.out.println(beautifulPairs);43}44}

Let us first understand what the program is going to ask. It asks to output the number of beautiful…

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Engineering

Computer Science

Can you explain this code? It is "Beautiful Pairs" Hackerrank question's solution.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Concept explainers

Bare bones programming language

Bare bones programming language is a low-level programming language that gives a detailed stepwise description of a program. It has a tight program design and in-depth understanding of the toolchain. It is based on the target environment and is used for safe coding practices. C programming language is a type of bare bones programming language.

Question

Can you explain this code? It is "Beautiful Pairs" Hackerrank question's solution.

15
public class Solution {
16
17
private static final int MAX_NUM = 100e; // max value of any number in array
%3D
18
19
public static void main(String[] args) {
Scanner scan = new Scanner (System.in);
20
21
int N = scan.nextInt();
int [] bucketA = new int[MAX_NUM + 1];
for (int i = 0; i < N; i++) {
bucketA[scan.nextInt ()]++;
22
23
24
25
26
int beautifu1Pairs = 0;
%3D
for (int i = 0; i < N; i++) {
27
28
int num = scan.nextInt();
29
if (bucketA[num] > 0) {
30
bucketA[num]--;
31
beautifulPairs++;
32
}
33
34
scan.close();
35
36
/* Accounts for changing 1 element in B */
37
if (beautifulPairs == N) {
38
beautifulPairs--;
} else {
39
40
beautifulPairs++;
41
42
System.out.println(beautifulPairs);
43
}
44
}

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