Can you explain this code for me please? It's urgent and it doesn't need to be detailed. It's about breadth first search distance.
Can you explain this code for me please? It's urgent and it doesn't need to be detailed. It's about breadth first search distance.
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Can you explain this code for me please? It's urgent and it doesn't need to be detailed. It's about breadth first search distance.
![public static Map<Integer, Integer> bfsDistance (DirectedGraph digraph, Integer start) {
Map<Integer, Integer> distance = new HashMap<Integer, Integer> ();
Set<Integer> keys = digraph.inDegree ().keySet ();
Queue<Integer> queue = new LinkedList<>();
int length = digraph.adjList.size();
boolean[] visited = new boolean[length];
int[] queue2 = new int[length];
queue2[start]=0;
queue.add (start);
visited [start]=true%;
distance.put(start,0);
while(!queue.isEmpty())
{
List<Integer> firstkey=digraph.adjList.get (queue.peek ());
for (int i =0;i<firstKey.size ();i++)
{
queue2 [firstkey.get(i)]=queue2 [queue.peek ()]+1;
if(visited [firstkey.get (i)]==false)
{
queue.add (firstkey.get (i));
distance.put (firstkey.get(i), queue2 [firstkey.get(i)]);
}
visited [firstKey.get(i)]=true;
}
queue.poll();
}
for (int i =0;i<length;i++)
{
if(!distance.containskey (keys.toArray () [i]))
distance.put((Integer)keys.toArray () [i],-1);
}
return distance;
}](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffc816d75-4ea9-45b6-b56b-06cb67af9ef8%2Fc25d4720-dc4d-479e-9712-4e4856ea390c%2Fnp0lh8_processed.png&w=3840&q=75)
Transcribed Image Text:public static Map<Integer, Integer> bfsDistance (DirectedGraph digraph, Integer start) {
Map<Integer, Integer> distance = new HashMap<Integer, Integer> ();
Set<Integer> keys = digraph.inDegree ().keySet ();
Queue<Integer> queue = new LinkedList<>();
int length = digraph.adjList.size();
boolean[] visited = new boolean[length];
int[] queue2 = new int[length];
queue2[start]=0;
queue.add (start);
visited [start]=true%;
distance.put(start,0);
while(!queue.isEmpty())
{
List<Integer> firstkey=digraph.adjList.get (queue.peek ());
for (int i =0;i<firstKey.size ();i++)
{
queue2 [firstkey.get(i)]=queue2 [queue.peek ()]+1;
if(visited [firstkey.get (i)]==false)
{
queue.add (firstkey.get (i));
distance.put (firstkey.get(i), queue2 [firstkey.get(i)]);
}
visited [firstKey.get(i)]=true;
}
queue.poll();
}
for (int i =0;i<length;i++)
{
if(!distance.containskey (keys.toArray () [i]))
distance.put((Integer)keys.toArray () [i],-1);
}
return distance;
}
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