Can you explain 4b? The answer is iodine is oxidized and chlorine is reduced. I'm just not sure where the Na goes and about the charges...Thank you!

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Can you explain 4b? The answer is iodine is oxidized and chlorine is reduced. I'm just not sure where the Na goes and about the charges...Thank you!

4. For each of the following oxidation-reduction reac-
tions of metals with nonmetals, identify which ele-
ment is being oxidized and which is being being re-
duced.
a. 4K(s) + O₂(g) → 2K₂O(s)
b. Cl₂(g) + 2Nal(aq) → 2NaCl(aq) + 1₂(s)
c. 2Co(s) + 3Cl₂(g) → 2CoCl3(s)
d. 2C(s) + O₂(g) → 2CO(g)
Transcribed Image Text:4. For each of the following oxidation-reduction reac- tions of metals with nonmetals, identify which ele- ment is being oxidized and which is being being re- duced. a. 4K(s) + O₂(g) → 2K₂O(s) b. Cl₂(g) + 2Nal(aq) → 2NaCl(aq) + 1₂(s) c. 2Co(s) + 3Cl₂(g) → 2CoCl3(s) d. 2C(s) + O₂(g) → 2CO(g)
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