Can you create a truth table for for P0 , P1 and an adder for it?

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Can you create a truth table for for P0 , P1 and an adder for it?
The image appears to depict a detailed handwritten multiplication process, likely for binary numbers, along with polynomial expansions.

### Binary Multiplication

**Step 1: Binary Representation**

- **A:** `10101010`
- **B:** `10101010`

These numbers are represented in binary digits, and there's a note indicating these are parts A and B.

**Step 2: Multiplication Setup**

The multiplication proceeds by aligning partial products under each other similarly to decimal multiplication:

```
      B0A1   B1A0
    B0A2    B1A1   B2A0
  B0A3   B1A2    B2A1   B3A0
B0A4   B1A3   B2A2    B3A1   B4A0
  B0A5   B1A4   B2A3   B3A2    B4A1   B5A0
    B0A6   B1A5   B2A4   B3A3   B4A2    B5A1   B6A0
      B0A7   B1A6   B2A5   B3A4   B4A3   B5A2   B6A1   B7A0
```

### Polynomial Expansion

Underneath the multiplication, polynomial expansions are presented. Each line is a summation of products and carries in:

- **P0** = B0A0
- **P1** = B0A1 + B1A0
- **P2** = B0A2 + B1A1 + B2A0 + Cin
- **P3** = B0A3 + B1A2 + B2A1 + B3A0 + Cin
- **P4** = B0A4 + B1A3 + B2A2 + B3A1 + B4A0 + Cin
- **P5** = B0A5 + B1A4 + B2A3 + B3A2 + B4A1 + B5A0 + Cin
- **P6** = B0A6 + B1A5 + B2A4 + B3A3 + B4A2 + B5A1 + B6A0 + Cin
-
Transcribed Image Text:The image appears to depict a detailed handwritten multiplication process, likely for binary numbers, along with polynomial expansions. ### Binary Multiplication **Step 1: Binary Representation** - **A:** `10101010` - **B:** `10101010` These numbers are represented in binary digits, and there's a note indicating these are parts A and B. **Step 2: Multiplication Setup** The multiplication proceeds by aligning partial products under each other similarly to decimal multiplication: ``` B0A1 B1A0 B0A2 B1A1 B2A0 B0A3 B1A2 B2A1 B3A0 B0A4 B1A3 B2A2 B3A1 B4A0 B0A5 B1A4 B2A3 B3A2 B4A1 B5A0 B0A6 B1A5 B2A4 B3A3 B4A2 B5A1 B6A0 B0A7 B1A6 B2A5 B3A4 B4A3 B5A2 B6A1 B7A0 ``` ### Polynomial Expansion Underneath the multiplication, polynomial expansions are presented. Each line is a summation of products and carries in: - **P0** = B0A0 - **P1** = B0A1 + B1A0 - **P2** = B0A2 + B1A1 + B2A0 + Cin - **P3** = B0A3 + B1A2 + B2A1 + B3A0 + Cin - **P4** = B0A4 + B1A3 + B2A2 + B3A1 + B4A0 + Cin - **P5** = B0A5 + B1A4 + B2A3 + B3A2 + B4A1 + B5A0 + Cin - **P6** = B0A6 + B1A5 + B2A4 + B3A3 + B4A2 + B5A1 + B6A0 + Cin -
Expert Solution
Step 1

Given that,

P0= B0A0

P1=B0A1+B1A0

In the given diagram, the values are: A0=0, A1=1, B0=0, B1=1

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