Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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question 3
![1) Why is hydrochloric acid not used directly in a reaction with copper metal to produce CuCl₂?
2) What is the maximum amount of CuCl which can be produced by the procedure in this
experiment if one starts with 1 g of copper metal?
3) In each redox reaction indicated in equations 1-6, indicate which species is oxidized and which
species is reduced..](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F07988e83-a3e9-4d52-ab01-33c4f0c30b8b%2F4f75fcb6-0c23-4dac-8b88-80cfc70ef07f%2Fn8vtm3m_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1) Why is hydrochloric acid not used directly in a reaction with copper metal to produce CuCl₂?
2) What is the maximum amount of CuCl which can be produced by the procedure in this
experiment if one starts with 1 g of copper metal?
3) In each redox reaction indicated in equations 1-6, indicate which species is oxidized and which
species is reduced..
![(Eq. 1)
(Eq. 2)
(Eq. 3)
(Eq. 4)
(Eq. 5)
(Eq. 6)
Cus) + 4 H* (aq) + 2NO3(aq) → Cu²+ (aq) + 2 NO₂(g) + 2 H₂O
2 H* (aq) + CO3² (aq) = H₂CO3(aq) CO2(g) + H₂O
Cu²+ (aq) + CO3(aq) CuCO3(6)
CUCO3(s) + 2 H+ (aq) + 4 Cl(aq) →CuCl(aq) + CO2(g) + H₂O
CuCl(aq) + Cu(s) + 4 Cl(aq)-2 CuCl4³(aq)
CuCl(aq) → CuClo) + 3 Cl(aq)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F07988e83-a3e9-4d52-ab01-33c4f0c30b8b%2F4f75fcb6-0c23-4dac-8b88-80cfc70ef07f%2Fh9cl0fg_processed.jpeg&w=3840&q=75)
Transcribed Image Text:(Eq. 1)
(Eq. 2)
(Eq. 3)
(Eq. 4)
(Eq. 5)
(Eq. 6)
Cus) + 4 H* (aq) + 2NO3(aq) → Cu²+ (aq) + 2 NO₂(g) + 2 H₂O
2 H* (aq) + CO3² (aq) = H₂CO3(aq) CO2(g) + H₂O
Cu²+ (aq) + CO3(aq) CuCO3(6)
CUCO3(s) + 2 H+ (aq) + 4 Cl(aq) →CuCl(aq) + CO2(g) + H₂O
CuCl(aq) + Cu(s) + 4 Cl(aq)-2 CuCl4³(aq)
CuCl(aq) → CuClo) + 3 Cl(aq)
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