can u help Write a brief conclusion on the answer that you obtain from the above question. Is it liable and okay to obtain this amount of error

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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can u help Write a brief conclusion on the answer that you obtain from the above question. Is it liable and okay to obtain this amount of error? Explain your point of view.

Cf ven
L- (oo m
A = 0.03 Scm?
i) sag
Correction
To
20°C
(sag correchin is
always negahie)
%3D
Lw?
Cs =
24 n P
Po =
E = 2x16 g cm2
%3D
s= Jox (1:5)?
24. (1)?. (lo)²
Pm
lokg
%3D
%3D
W = 1-skg
Tm
31° C
M.L = 1539.28m
Cs= 0•028/25 m (-ve)
f spons
it tope is supporfed at ends , so number
n-
no.
n= 1
i) Temperafure
corretion
So
I spon will be 1
(7= La ( Tm To)
Pull Correcfion
Cp= (Pm-P.)xL
in)
AXE
= loox It6 xt5x (31 - »)
= luox I1:6 x (6x (31 - 20
(lo-12)x l..
0-0 35 x 2x106
%3D
= 0.01276 m
-3
p = - 2.857 x 1o
answer provided by you length used
is 1539.28 which is incorrect as
In the
Total correctin (C)
L is
C= 0•01276 - 0·0 28125 - 2-857x16
L is lengh f tope-
- 0-018222 m C too short)
Correct leng th ef line
L'x ML
L
30-0-o18222x 15 39-28
%3D
30
C.L = 1538:345m
%3D
Mence correct length will be
1538.345m
Transcribed Image Text:Cf ven L- (oo m A = 0.03 Scm? i) sag Correction To 20°C (sag correchin is always negahie) %3D Lw? Cs = 24 n P Po = E = 2x16 g cm2 %3D s= Jox (1:5)? 24. (1)?. (lo)² Pm lokg %3D %3D W = 1-skg Tm 31° C M.L = 1539.28m Cs= 0•028/25 m (-ve) f spons it tope is supporfed at ends , so number n- no. n= 1 i) Temperafure corretion So I spon will be 1 (7= La ( Tm To) Pull Correcfion Cp= (Pm-P.)xL in) AXE = loox It6 xt5x (31 - ») = luox I1:6 x (6x (31 - 20 (lo-12)x l.. 0-0 35 x 2x106 %3D = 0.01276 m -3 p = - 2.857 x 1o answer provided by you length used is 1539.28 which is incorrect as In the Total correctin (C) L is C= 0•01276 - 0·0 28125 - 2-857x16 L is lengh f tope- - 0-018222 m C too short) Correct leng th ef line L'x ML L 30-0-o18222x 15 39-28 %3D 30 C.L = 1538:345m %3D Mence correct length will be 1538.345m
heres the question:A 100- m steel tape is used to measure the distance of the line and
found to be 1539.28 m long. During measurement, the tape is supported the ends under a
pull of 10 kg and the observed mean temperature is 31 deg. celsius. The tape is of
standard temperature of 20 deg. celsius and a tension of 12 kg. The cross sectional area of
the tape is 0.035 sq. cm. The coefficient of linear expansion is 0.0000116/ deg. celsius and
the modulus of elasticity of steel is 2.0 x 106 kg/ sq. cm. The tape weighs 1.5kg.
the attached photo is the answer.
can u help Write a brief conclusion on the answer that you obtain from the above
question. Is it liable and okay to obtain this amount of error? Explain your point of view.
Transcribed Image Text:heres the question:A 100- m steel tape is used to measure the distance of the line and found to be 1539.28 m long. During measurement, the tape is supported the ends under a pull of 10 kg and the observed mean temperature is 31 deg. celsius. The tape is of standard temperature of 20 deg. celsius and a tension of 12 kg. The cross sectional area of the tape is 0.035 sq. cm. The coefficient of linear expansion is 0.0000116/ deg. celsius and the modulus of elasticity of steel is 2.0 x 106 kg/ sq. cm. The tape weighs 1.5kg. the attached photo is the answer. can u help Write a brief conclusion on the answer that you obtain from the above question. Is it liable and okay to obtain this amount of error? Explain your point of view.
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