Can the idea of joint random variables apply to more than two variables or is it just strictly like an X and a Y variable? Explain in 1-2 sentences. Thanks in advance
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Can the idea of joint random variables apply to more than two variables or is it just strictly like an X and a Y variable? Explain in 1-2 sentences. Thanks in advance!
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- Please solve both questions. Do not answer if you can't answer both. Show all steps. 1. Three cards are chosen at random from a shuffled deck of cards. Determine theprobability of each card belonging to a different suit. 2. A bag contains 4 red balls, 3 orange balls, and 2 green balls. If three balls are chosenat random without replacement, what is the probability that all three balls areorange?Refer to the table which summarizes the results of testing for a certain disease. Positive Test Result Negative Test Result Subject has the disease 8 1 Subject does not have the disease 2 9 A test subject is randomly selected and tested for the disease. Leave your answers in fraction form. What is the probability of choosig a subject that contain disease? What is the probability of choosing a test subject with positive test result and contain the disease? What is the probability that the test result is negative given the subject has the disease?Hello. Could anyone help me on this question? I have tried it four times and only one attempt left. What I am confusing is that some choice are not individual and variables. Like all young children, children who eat snack and cartoon characters. But if i leave them there, it shows me I am wrong. Pls help me on this and explanation would be appreciated. Thanks!
- Due to current pandemic we are having online classes, Harish is also having online classes. He is having a quiz this weekend. In the quiz, Harish either guesses (or) copies from net(or) knows the answer to a multiple-choice question with 4 choices. Probability that he makes a guess is 1/3. He copies the answer is 1/6. The probability that his answer is correct given that he copied it is 1/8. Find the probability that he knew the answer to the question. Given that he correctly answered it.Kindly correct solution by law of probability, article Statistics and ProbabilityPlease don't copy.
- Needs Complete solution with 100 % accuracy.I need the answer as soon as possibleAn ice cream parlor serves 10 flavors of ice cream. Carrie and Jimmy each randomly and independently choose 3 out of those 10 flavors. Use the method of indicators to find the expected number of flavors chosen by both Carrie and Jimmy and simplify your final answer**** ****Each person has to choose 3 different flavors (Vanilla- Vanilla-Chocolate is not ok) but their flavors are allowed to overlap (Chocolate-Vanilla-Strawberry for Carrie and Chocolate- Blueberry-Mint for Jimmy is ok). The order of flavors doesn’t matter.
- Three friends are having a debate. They recently read that on average Americans drive 16 miles each way when computing to work by car (ABC News, 2007). Friend A suspects that the mean for Colorado residents is likely lower than the national average because the population density of Colorado increases the likelihood that people live closer to their jobs, while friend B suspects the mean for Colorado residents is likely higher than the national average. Friend C does not find either argument very convincing and instead suspects that the mean for Colorado residents is no different from the US population mean. The three friends bet a dinner at Alinea and set out to resolve the debate. Using a random sample of 20 Colorado residents, they calculate the mean for their sample to be 14.23 miles with a standard deviation of 2.34. The three friends did not pay very close attention in their statistics class, so they need your help making sense of these numbers. Compute the 95% confidence…You are given a two dice with 4 sides each, with equal probability of landong on all sides. Dice one has values 1 - 4 and the second has values 5-8. The low-valued die (dice one) is rolled first. If you get a 1 or 2, then you roll the high-valued die (dice 2). If you get 3 or 4, you roll the low-valued die. X= value of the 1st roll Y = value of the 2nd roll Z = X + Y %3D Find H(X), H(Y), H(Z) Find H(Y|X) Find H(X,Y), H(XIҮ) Find I (X;Y)Please help with explanation
