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Can someone kindly explain how the answer sheet got (1,0) and (2,1)?

Can someone kindly explain how the answer sheet got (1,0) and (2,1)?

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Can someone kindly explain how the answer sheet got (1,0) and (2,1)? I am asked to find the domain and range, asymptotes, intercepts and transformation. Thank you so much.
(b) Graph y = log3(x-3) - 6 horizontal shift : right 3 vertical shift: down 6 vertical asymptote: >= 3 no horizontal asymptote domain: {XER | x 73} range:{YER} x-int: C732, 0) y-int : none parent function : y=logzCx) -10 -8 -6 vertical asymptote >=1 -4 10 -2 Y 12 8 6 4 2 -2 -4 -6 -8 -10 1=' TT 2 x=3 tco 6 8 +X 10
Transcribed Image Text:(b) Graph y = log3(x-3) - 6 horizontal shift : right 3 vertical shift: down 6 vertical asymptote: >= 3 no horizontal asymptote domain: {XER | x 73} range:{YER} x-int: C732, 0) y-int : none parent function : y=logzCx) -10 -8 -6 vertical asymptote >=1 -4 10 -2 Y 12 8 6 4 2 -2 -4 -6 -8 -10 1=' TT 2 x=3 tco 6 8 +X 10
ZDbt71 b) Graph y = log₂ (x-2)-3 Base Fuc, y= log₂x shift right 2 (1,0) (2,1) x=0 I →shift down 3 x=2 Final fuc: D:{XER/x>2} R: {y€R} asymp: x=2 анутрі x-int: (10,0) -10 -8 -6 -4 X=DA 10 -2 8 61- 4 T -2 -4 -6 -8 -10- TO 2- J x=2 4 6 y= log₂x 10 y= log₂ (x-2) -3 HW: Graphs of Exponential Functions Worksheet, Pg. 338 #1-8
Transcribed Image Text:ZDbt71 b) Graph y = log₂ (x-2)-3 Base Fuc, y= log₂x shift right 2 (1,0) (2,1) x=0 I →shift down 3 x=2 Final fuc: D:{XER/x>2} R: {y€R} asymp: x=2 анутрі x-int: (10,0) -10 -8 -6 -4 X=DA 10 -2 8 61- 4 T -2 -4 -6 -8 -10- TO 2- J x=2 4 6 y= log₂x 10 y= log₂ (x-2) -3 HW: Graphs of Exponential Functions Worksheet, Pg. 338 #1-8
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