Can someone kindly explain how the answer sheet got (1,0) and (2,1)?

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Can someone kindly explain how the answer sheet got (1,0) and (2,1)? I am asked to find the domain and range, asymptotes, intercepts and transformation. Thank you so much.
(b) Graph y = log3(x-3) - 6
horizontal shift :
right 3
vertical shift:
down 6
vertical asymptote: >= 3
no horizontal asymptote
domain: {XER | x 73}
range:{YER}
x-int: C732, 0)
y-int
: none
parent function : y=logzCx)
-10
-8
-6
vertical
asymptote >=1
-4
10
-2
Y
12
8
6
4
2
-2
-4
-6
-8
-10
1='
TT
2
x=3
tco
6
8
+X
10
Transcribed Image Text:(b) Graph y = log3(x-3) - 6 horizontal shift : right 3 vertical shift: down 6 vertical asymptote: >= 3 no horizontal asymptote domain: {XER | x 73} range:{YER} x-int: C732, 0) y-int : none parent function : y=logzCx) -10 -8 -6 vertical asymptote >=1 -4 10 -2 Y 12 8 6 4 2 -2 -4 -6 -8 -10 1=' TT 2 x=3 tco 6 8 +X 10
ZDbt71
b) Graph y = log₂ (x-2)-3
Base Fuc,
y= log₂x shift right
2
(1,0)
(2,1)
x=0
I
→shift down
3
x=2
Final fuc:
D:{XER/x>2}
R: {y€R}
asymp: x=2
анутрі
x-int: (10,0)
-10
-8
-6
-4
X=DA
10
-2
8
61-
4
T
-2
-4
-6
-8
-10-
TO
2-
J
x=2
4
6
y= log₂x
10
y= log₂ (x-2)
-3
HW: Graphs of Exponential Functions Worksheet, Pg. 338 #1-8
Transcribed Image Text:ZDbt71 b) Graph y = log₂ (x-2)-3 Base Fuc, y= log₂x shift right 2 (1,0) (2,1) x=0 I →shift down 3 x=2 Final fuc: D:{XER/x>2} R: {y€R} asymp: x=2 анутрі x-int: (10,0) -10 -8 -6 -4 X=DA 10 -2 8 61- 4 T -2 -4 -6 -8 -10- TO 2- J x=2 4 6 y= log₂x 10 y= log₂ (x-2) -3 HW: Graphs of Exponential Functions Worksheet, Pg. 338 #1-8
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