can someone help explain the logic for this both of these pieces of code and why they are getting that output A. #include #define quick(x,y) x*x+y*y main( ) {float x=1.5,y=2.0,z=18.0,w=3.0,t=2.0; float a = 5.0, b=6.0,c = 4.0,d=10.0,e=12.0; int i=7; x = y+z/w*t; a = 10/3*y; t = c*quick(w+1.0,3.0*t); d = b++*c; e = (float)(i/2); printf("%f %f %f",x,a,t); printf(" %f %f %f",b,d,e); } output: 14.000000 6.000000 52.000000 7.000000 24.000000 3.000000 B. #include int f(int n,int m); main( ) {int n=5,m=8,k=10,j=13,i=0; for(i=1;i<3;++i) {j = f(m,k-2*i); printf("%d %d %d %d\n",j,n,m,k); } } int f(int n, int m) {int k; if(n>m) k=n%m+1; k=m%n--; return k; } output: 0 5 8 10 6 5 8 10
can someone help explain the logic for this both of these pieces of code and why they are getting that output A. #include #define quick(x,y) x*x+y*y main( ) {float x=1.5,y=2.0,z=18.0,w=3.0,t=2.0; float a = 5.0, b=6.0,c = 4.0,d=10.0,e=12.0; int i=7; x = y+z/w*t; a = 10/3*y; t = c*quick(w+1.0,3.0*t); d = b++*c; e = (float)(i/2); printf("%f %f %f",x,a,t); printf(" %f %f %f",b,d,e); } output: 14.000000 6.000000 52.000000 7.000000 24.000000 3.000000 B. #include int f(int n,int m); main( ) {int n=5,m=8,k=10,j=13,i=0; for(i=1;i<3;++i) {j = f(m,k-2*i); printf("%d %d %d %d\n",j,n,m,k); } } int f(int n, int m) {int k; if(n>m) k=n%m+1; k=m%n--; return k; } output: 0 5 8 10 6 5 8 10
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
can someone help explain the logic for this both of these pieces of code and why they are getting that output
A.
#include <stdio.h>
#define quick(x,y) x*x+y*y
main( )
{float x=1.5,y=2.0,z=18.0,w=3.0,t=2.0;
float a = 5.0, b=6.0,c = 4.0,d=10.0,e=12.0;
int i=7;
x = y+z/w*t;
a = 10/3*y;
t = c*quick(w+1.0,3.0*t);
d = b++*c;
e = (float)(i/2);
printf("%f %f %f",x,a,t);
printf(" %f %f %f",b,d,e);
}
output:
14.000000 6.000000 52.000000 7.000000 24.000000 3.000000
B.
#include <stdio.h>
int f(int n,int m);
main( )
{int n=5,m=8,k=10,j=13,i=0;
for(i=1;i<3;++i)
{j = f(m,k-2*i);
printf("%d %d %d %d\n",j,n,m,k);
}
}
int f(int n, int m)
{int k;
if(n>m)
k=n%m+1;
k=m%n--;
return k;
}
output:
0 5 8 10
6 5 8 10
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