Can someone explain the step by step process of this solution like how it happened, including terms (ex. V, A, Q)

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Can someone explain the step by step process of this solution like how it happened, including terms (ex. V, A, Q)

ANS,
STEP I:
Given data:
velocity v= 2m/see
16 tubes in a single Pass Cooler
Diameter of
dz 30mm =) 0.03m
the tube
density 8= 0.85 9lei
Transcribed Image Text:ANS, STEP I: Given data: velocity v= 2m/see 16 tubes in a single Pass Cooler Diameter of dz 30mm =) 0.03m the tube density 8= 0.85 9lei
16 x Yolume flow Yate of one tobe
STEP 2:
distauce
In one second fluild Covered
avea of
volume flow in
one second = Cvoss section
second
the tord
the tube X distemce oveved in one
Total volwme flow rate =
Q: (6 × AメV
= 16x Rx V
16x Co.03)x2
Q = 0.022619 m3/see
lit (sec
Q= 0. 6226l9 X1000
Q : 22.61· lit/sec
[ima/sec: lo0o lite
- 23 lit/sec
Hence
Answey
OPtion (d)
Transcribed Image Text:16 x Yolume flow Yate of one tobe STEP 2: distauce In one second fluild Covered avea of volume flow in one second = Cvoss section second the tord the tube X distemce oveved in one Total volwme flow rate = Q: (6 × AメV = 16x Rx V 16x Co.03)x2 Q = 0.022619 m3/see lit (sec Q= 0. 6226l9 X1000 Q : 22.61· lit/sec [ima/sec: lo0o lite - 23 lit/sec Hence Answey OPtion (d)
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