Hi, Please answer all parts. Last answer was incorrect. - Can normality be assumed?Last parts, the options are:- P Value : greater than or Less than- Null hypothesis: Fails to be rejected or Is rejected- Mean GPA: Sufficient or Insufficient ### Statistical Analysis of Mean Class GPAs#### InstructionsUse Sheet 1 of the Excel file to answer the following questions.#### ScenarioA school administrator believes that the mean class GPAs for a given course are higher than the preferred mean of 2.75 at a significance level of 0.05. The administrator checks a randomly chosen sample of 50 classes. You are required to create a histogram, and calculate the sample mean (\(\bar{x}\)), the t-statistic (\(t\)), and the p-value (\(p\)).#### Steps1. **From the histogram, can normality be assumed?** - **Dropdown Options:** - Yes - No2. **Calculate the sample mean (\(\bar{x}\)):** - **Input Field:** Example format \( \bar{x} = 1.234 \)3. **Calculate the t-statistic (\(t\)):** - **Input Field**4. **Determine the p-value (\(p\)):** - **Input Field**5. **Compare the p-value with the significance level \(0.05\):** - **Dropdown Options:** More/Less6. **Determine if enough evidence exists to support the claim that the mean GPA is greater than 2.75:** - **Dropdown Options:** Strong/Weak#### Example Choices- Since the p-value is [Pick: More/Less] than the significance level \(0.05\), the null hypothesis is [Pick: Rejected/Not Rejected].- [Pick: Strong/Weak] evidence exists that the mean GPA is greater than 2.75.#### Interface Elements- **Check Button:** - Validate your answers by clicking the "Check" button.- **Next Button:** - Proceed to the next set of questions by clicking the "Next" button.##### Navigation- The interface provides a navigation bar with options to go through different pages or questions (page 1 of 3 shown).By following the steps and using the provided tools, you can effectively determine if the sample data supports the hypothesis that the mean GPA for the given course is greater than 2.75. ### Data Analysis of Field1 ValuesThe dataset consists of numerical values for a field labeled 'Field1.' Below is a detailed analysis of these values along with a histogram and cumulative percentage graph for better visualization of the data distribution.#### Data Values```3.09, 2.73, 2.58, 2.68, 2.84, 2.68, 2.62, 2.35, 2.62, 2.63,2.77, 2.72, 3.03, 2.71, 2.96, 2.74, 3.01, 2.88, 2.68, 2.83,3.02, 2.83, 2.71, 2.67, 2.79, 2.65, 2.56, 2.78, 2.89, 2.40,2.38, 2.41, 2.83, 2.86, 3.01, 2.80, 2.84, 2.95, 2.75, 2.93,2.48, 2.34, 2.97, 2.85, 2.74, 2.84, 3.10, 2.62, 2.77```#### Descriptive Summary1. **Minimum Value:** 2.342. **Maximum Value:** 3.103. **Mean Value:** [Calculation Needed]4. **Median Value:** [Calculation Needed]#### Histogram and Cumulative Frequency Graph**Figure: Frequency of 'Field1'**![Frequency of Field1](graph-image-placeholder)The histogram shown here represents the frequency distribution of the 'Field1' values. The x-axis is categorized into bins that represent data ranges. Each bar's height indicates the number of data points within that bin.**Categories:**- (2.64, 2.74): Highest frequency with approximately 12 occurrences.- (2.74, 2.84): Around 8 occurrences.- (2.84, 2.94): Around 10 occurrences.- (2.94, 3.04): Approximately 7 occurrences.- (2.34, 2.44): About 4 occurrences.- (

Name: Hi, Please answer all parts. Last answer was incorrect. - Can normalit
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: Hi, Please answer all parts. Last answer was incorrect. - Can normality be assumed?Last parts, the options are:- P Value : greater than or Less than- Null hypothesis: Fails to be rejected or Is rejected- Mean GPA: Sufficient or Insufficient ### Stati