Can Kirchhoff’s rules be applied to simple series and parallel circuits or are they restricted for use in more complicated circuits that are not combinations of series and parallel? Explain.
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Kirchhoff’s Circuit Laws (KCL and KVL)
Can Kirchhoff’s rules be applied to simple series and parallel circuits or are they restricted for use in more
complicated circuits that are not combinations of series and parallel? Explain.
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- b) For the circuit shown below, R1 = 4.40, R2 = 60, R3 = 50, R4 = 42 and the battery voltage is 12V. R3 R4 R2 R1 i) The equivalent resistance of the circuit is = ii) The source current is = A iii) The voltage drop across R2 is = iv) The current through R4 is = A v) The power dissipated across Ri is = Wplease do answer all, the choices each question are on the right side. thank you so much! <3Which of the following statements are true about a parallel circuit? List all that apply. Parallel circuits are characterized by the fact that there are multiple pathways by which charge can travel from the + terminal to the - terminal. During any single loop of charge around a parallel circuit, the charge will pass through each resistor in the circuit. The overall resistance of a circuit increases as more and more resistors are placed in parallel in the circuit. The total current in a circuit increases as more and more resistors are placed in parallel in the circuit. Suppose that three identical resistors with a resistance of 3-ohms are placed in parallel with a 12-Volt battery. The current in the circuit is 1 Amp. Suppose that three identical resistors with a resistance of 3-ohms are placed in parallel with a 12-Volt battery. The electric potential difference across each resistor is 12 Volts. Suppose that two identical resistors are placed in parallel with a 12-Volt battery. The…
- 2) Consider the Circuit below. Determine the equivalent capacitance of the circuit and the charges and voltages across all 4 capacitators for arbitrary Voltage, V. Determine the total energy stored in the circuit. C₁ C₂ HH C₂ C₁A circuit diagram is shown in the figure below. You do not need to solve the whole circuit for the following questions. 1122 13 Q2 M 6.0 V E + g 0.20A 15 92 m 1992 W 1992 0.40 A b 11 0.10A ← What is the emf of the battery between points d and g? [Select] m 30 22 w 25 92 m 21 22 21.0 V 14.0 V + C 1892 10.70A h Use the current direction assumed in the diagram. What is the current I₂? [Select] Point g is grounded (i.e., V₂ = 0 V), as shown in the diagram. What is the electric potential at point f? [Select]Which of the following differences between a parallel and series circuits is FALSE? Series: The electric current has a single path to flow through. Parallel: The electric current has multiple paths to flow through. Series: When resistors are put in a series circuit, the voltage across each resistor is different even though the current flow is the same through all of them. Parallel: When resistors are put in a parallel circuit, the voltage across each of the resistors is the same. Series: If one component breaks down, the whole circuit will burn out. Parallel: Other components will function even if one component breaks down, each has its own independent circuit Series: The current flowing through each component combines to form the current flow through the source. Parallel: The same amount of current flows through all the components.
- For the following circuit: Calculate : a) The equivalent resistance of the circuit. b) Total circuit current. c) The currents I2 and I3. d) Voltages V1, V2 and V3.1. Initially, for the circuit shown above, the switch S is open and the capacitor charge is 80 µC. The switch S is closed at time t = 0. The capacitor charge when the time t is equal to 50.0 s is closest to: Group of answer choices a. 64 µC b. 72 µC c. 48 µC d. 80 µC e. 56 µC 2. What is the value of the time constant of the RC circuit shown in question 11? a. 50.0 s b. 97.6 s c. 2.62 s d.0.381 s e.0.0102 s%3D Ry =? www V = 9 Volts V= 9 Valts Calculate the circuit For the above circuit, say R1 = 10 N on the main line. R2 = 20 N and R3 = 100 Ω. 1) Since R2 and R3 are in parallel, we can use equation (3) to calculate the equivalent total resistor R23 . 2) After that since R1 and R23 are in series, we can use equation (2) to calculate the overall total RT. 3) The battery V=9 volts is known, Ohm's can be applied to RT, total current can be calculated, and the total current is equal to I1 4) With I, and R1, Ohm's law can help us to get V1 5) V1 +V½ (or V3) = 9 volts, we get V2 6) Again, use Ohm's to get I2 and I3. The circuit is solved. %3D Do the calculations. Fill in the table1. Table1---circuit calculation variables Calculated results V1 V2 I2 V3 I3
- 27. * (a) Write two loop rule equations and one junc- tion rule equation for the circuit in Figure P19.27. (b) Use these equations to determine the current in each branch of the circuit for the case in which R₁ = 50, R₂ = 30 , R₂ = 15 N, and ε = 120 V. 28. (a) Write Kirchhoff's loop rule for the circuit shown in Figure P19.28 for the case in which E₁ = 20 V. &₂ = 8 V, R₁ = 30 2. R₂ = 20 02. FIGURE P19.27 R₁ R₂ R₂ wwwRefer to the given circuit. C1 = 5 µF C3 = 8 µF C2 = 4 µF C4 = 6 µF C5 = 4 µF DURACELL VT = 12 V How much energy is present across the plates of capacitor #1 (C1)? Select one: а. 103.68 micro Joules b. 161.80 micro Joules С. 69.12 micro Joules d. 79.81 micro JoulesCan you explain how my profeddor got the answer