Perform double integration of the bending moment equations. You will obtain deflections in this form: VEI = F(x) + С₁x + C3 vEI = G(x) + C₂x + C4 for 0 ≤ x ≤ a for a ≤x≤ a+b Calculate: e) the value of the integration constant C₂. Enter your answer in kNm² to three decimal places. Answer:
Perform double integration of the bending moment equations. You will obtain deflections in this form: VEI = F(x) + С₁x + C3 vEI = G(x) + C₂x + C4 for 0 ≤ x ≤ a for a ≤x≤ a+b Calculate: e) the value of the integration constant C₂. Enter your answer in kNm² to three decimal places. Answer:
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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And do g) the value of the deflection at point C in mm to three decimal points
Transcribed Image Text:Part B
Perform double integration of the bending moment equations. You will obtain deflections in
this form:
VEI F(x) + C₁x + C3
vEI = G(x) + C₂x + C4
Calculate:
e) the value of the integration constant C₂. Enter your answer in kNm² to three decimal places.
Answer:
for 0 ≤x≤a
for a ≤x≤ a+ b
Check
f) the value of the integration constant C4. Enter your answer in kNm² to three decimal places.
Transcribed Image Text:A steel beam, of lengths a = 6 m and b=4 m and a hollow box cross section, is supported by a hinge support A and roller
support B, see Figure Q.1. The width and height of the cross section are 200 mm and 300 mm, respectively, and the wall
thickness of the cross section is 5 mm. The beam is under a distributed load of the intensity that linearly varies from q=
0 kN/m to q= 4.3 kN/m for AB span; and is constant with q= 4.3 kN/m for BC span. The Young's modulus of steel is 200
GPa.
A
y, v
a
5 mm
200 mm
Figure Q.1
9
300 mm
B
b
C
X
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