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Create an Java Postfix converter using the algorithm provided. Thank you

Create an Java Postfix converter using the algorithm provided. Thank you

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Create an Java Postfix converter using the algorithm provided.

Thank you

 

Algorithm convertToPostfix (infix) 11 Converts an infix expression to an equivalent postfix expression. operatorStack = a new empty stack postfix = a new empty string while (infix has characters left to parse) { nextCharacter = next nonblank character of infix switch (nextCharacter) { } } while { case variable: Append nextCharacter to postfix break case 'Λ' operatorStack.push(nextCharacter) break case '+': case : case while (!operatorStack.isEmpty() and precedence of nextCharacter <= precedence of operatorStack.peek ()) Append operatorStack. peek () to postfix operatorStack.pop() { } break case '(': I operatorStack.push(nextCharacter) I* I operatorStack.push(nextCharacter) break case ')': // Stack is not empty if infix expression is valid operatorStack.pop() = topOperator while (topOperator != '(') { : case '/' : Append topOperator to postfix topOperator = operatorStack.pop() (!operatorStack.isEmpty()) } break default: break // Ignore unexpected characters } return postfix topOperator = operatorStack.pop() Append topOperator to postfix
Transcribed Image Text:Algorithm convertToPostfix (infix) 11 Converts an infix expression to an equivalent postfix expression. operatorStack = a new empty stack postfix = a new empty string while (infix has characters left to parse) { nextCharacter = next nonblank character of infix switch (nextCharacter) { } } while { case variable: Append nextCharacter to postfix break case 'Λ' operatorStack.push(nextCharacter) break case '+': case : case while (!operatorStack.isEmpty() and precedence of nextCharacter <= precedence of operatorStack.peek ()) Append operatorStack. peek () to postfix operatorStack.pop() { } break case '(': I operatorStack.push(nextCharacter) I* I operatorStack.push(nextCharacter) break case ')': // Stack is not empty if infix expression is valid operatorStack.pop() = topOperator while (topOperator != '(') { : case '/' : Append topOperator to postfix topOperator = operatorStack.pop() (!operatorStack.isEmpty()) } break default: break // Ignore unexpected characters } return postfix topOperator = operatorStack.pop() Append topOperator to postfix
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