Camila, an Analytical Chemistry student, determined the masses of four transfers of a solution to be 8.8835 g, 8.5282 g. 9.2388 g, and 8.9723 g.Camila weighed a final portion to be 8.3505 g.Question 1: Using the Grubbs test, is the fifth portion an outlier to 95% confidence?Submit Answer Tries 0/99Question 2. Using the masses that do not fail the Grubb's Test, calculate the average mass of solution transfered by Camila:Submit Answer Tries 0/999Question 3. Calculate the standard deviation of the appropriate masses of solution transfered by Camila:Submit Answer Tries 0/99

It is required to identify whether the fifth portion is an outlier using Grubbs test at 95%…

Answered: Camila, an Analytical Chemistry…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A survey is conducted to determine if there is a difference in the proportion of students, parents, and The conditions for inference are met. The chi-square test statistic is 0.19 and df = 2. What is the appropriate decision using a = 0.05? teachers who volunteer at least once a month. To investigate, a random sample of 45 students, 25 parents, and 12 teachers was selected from a large high school. The data are displayed in the table. Find the chi-square table here. Because the P-value is less than a = 0.05, the null hypothesis should be rejected. Student Parent Teacher Because the P-value is less than a = 0.05, the null hypothesis should not be rejected. Yes 24 12 Volunteer? No 21 13 Because the P-value is greater than a = 0.05, the null hypothesis should be rejected. The researcher would like to test these hypotheses: Because the P-value is greater than a = 0.05, the null hypothesis should not be rejected. Họ: There is no difference in the distribution of responses among these three…
Everest auto industry produces bearing for Mahindra Motor Corporation. The precision of radius of bearing is very important for its successful functioning. To check the variability in the bearing radius, the company randomly selected ten bearings and measured the radius, the result of which is as shown in the table below. #no Nominal radius (cm) #no Nominal radius (cm) 1 2.70 6 2.59 2 2.65 7 2.73 3 2.75 8 2.64 4 2.55 9 2.88 5 2.76 10 2.83 Calculate the sample standard deviation for the above data. Construct a box plot and check whether there is any outlier data in the data distribution. Based on the comparison between the mean and the quartile, identify the shape of the data distribution. Calculate the 65th percentile and interpret the result. What is the range of the data distribution? Explain its meaning.
Q3. Calculate Estimated Standard error (SE)from the following data: 3 4 5 2 1 y 3 4 6.
r:32. Compute the median weight of the rabbits from the following data: Serial Number: 1 3 4 Weight in gms: 120 150 110 190 160 95.
(3-B is needed to answer it I am only asking for question 4.) 3) You go out and collect the following estimates of earthworms / acre:54,276 57,378 51,108 66,190 66,232 59,018 57,159These data yield the following: ̄y = 59,765.86, and s = 5,689.606a) Construct a 90% CI for these data.b) Construct a 99% CI for these data.c) Darwin once estimated that an acre of soil had about 50,000 worms in it. Is his estimateconsistent with the data above? (Historical note: His estimate was considered way too high inhis day). 4) Consider the results of 3(b). Notice that all the data fit within the 99% confidence interval. Is thisusually the case (in other words, will a 99% CI contain most of the observations)?Caution: a lot of people get this wrong! Here's a hint: suppose you had measured the worms in6000 acres (instead of just 7). What happens to the confidence interval? If you're not sure,substitute 6,000 for 7 in your calculation for (b) to see what happens.
Phosphorous is a chemical that is found in many household cleaning products. Unfortunately, phosphorous also finds its way into surface water, where it can harm fish, plants, and other wildlife. Two methods of phosphorous reduction are being studied. At a random sample of 7 locations, both methods were used and the total phosphorous reduction (mg/L) was recorded. Note: For degrees of freedom d.f. not in the Student's t table, use the closest d.f. that is smaller. In some situations, this choice of d.f. may increase the P-value a small amount and thereby produce a slightly more "conservative" answer. Things that are labelled i underneath a b c, etc are all part of that part.
a survey is conducted to compare the proportions of men and women whoaccess their bank statements online. Denoting the population propotions by Pm and Pw, a two-proportion z-test is carried out to test Ho: pm = pw against Ha: pm > pw. The values of the test statistic is found to be z = 0.784, and the p-value for the test is found to be 0.216. Which of the following is the correct interpretation of the p-value? a) given that ha is true, the probability of getting a value of z at least as large as 0.784 is 0.216. b) given that ho is true, the probability of getting a value of z at least as large as 0.784 is 0.216. c) given the results of the survey, the probability that Pm > Pw is 0.216. d) given the results of the survey, the probability that Pm = Pw is 0.216. e) none of the above
Only answer the questions typed: A. indicate whether it's one or two sidedB. Indicate whether it's a test of means or proportionsC. Write out the expression for determining the P-value
UPVOTE WILL BE GIVEN. Solve in 2 decimal places. No long explanation needed. Box the final answer.
Phosphorous is a chemical that is found in many household cleaning products. Unfortunately, phosphorous also finds its way into surface water, where it can harm fish, plants, and other wildlife. Two methods of phosphorous reduction are being studied. At a random sample of 7 locations, both methods were used and the total phosphorous reduction (mg/L) was recorded. Note: For degrees of freedom d.f. not in the Student's t table, use the closest d.f. that is smaller. In some situations, this choice of d.f. may increase the P-value a small amount and thereby produce a slightly more "conservative" answer. Site 1 2 3 4 5 6 7 Method I: 0.013 0.020 0.015 0.055 0.007 0.002 0.010 Method II: 0.014 0.045 0.017 0.039 0.017 0.001 0.013 Do these data indicate a difference (either way) in the average reduction of phosphorous between the two methods? Use α = 0.05. (Let d = Method I − Method II.) (i) What is the level of significance? What is the value of the sample test statistic? (Round…
To test whether the mean time needed to mix a batch of material is the same for machines produced by three manufacturers, the Jacobs Chemical Company obtained the following data on the time (in minutes) needed to mix the material. Compute the values below (to 2 decimals, if necessary). Sum of Squares, Treatment Sum of Squares, Error a. Use these data to test whether the population mean times for mixing a batch of material differ for the three manufacturers. Use a = 0.05. Mean Squares, Treatment 0000 Mean Squares, Error Calculate the value of the test statistic (to 2 decimals). 1 17 23 21 19 What conclusion can you draw after carrying out this test? - Select your answer - Manufacturer 2 28 26 31 27 + 3 18 17 21 20 The p-value is - Select your answer - What is your conclusion? - Select your answer - b. At the a = 0.05 level of significance, use Fisher's LSD procedure to test for the equality of the means for manufacturers 1 and 3. Calculate Fisher's LSD Value (to 2 decimals).
Several methods of estimating the number of seeds in soil samples have been developed by ecologists. An article gave the accompanying data on the number of seeds detected by the direct method and by the stratified method for 27 soil specimens. Specimen 1 2 3 4 5 6 7 8 9 10 11 12 13 14 Direct 21 33 0 60 20 61 40 8 13 93 1 68 77 21 Stratified 8 37 8 57 53 61 28 8 8 100 0 57 68 53 Specimen 15 Find the test statistic. (Round your answer to two decimal places.) t = 16 17 18 19 20 21 22 23 24 25 26 27 Direct Find the df. (Round your answer down to the nearest whole number.) df = 33 0 37 17 93 1 40 21 0 8 13 Use technology to find the P-value. (Round your answer to four decimal places.) P-value = 17 40 Stratified 28 0 37 13 93 13 48 21 0 13 40 Do the data provide sufficient evidence to conclude that the mean number of seeds detected differs for the two methods? Test the relevant hypotheses using a = 0.05. (Use direct stratified.) 13 77

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