Calorimetry In a kitchen there are two identical pans that have been previously heated, one of the pans is filled with 1/2 liter of Water at 100◦C and the other with 1/2 liter of oil at 130◦C. After that, no there is more fire that keeps introducing heat to both liquids. In that instant, a person who had cut 300 grams of potato into small cubes at a temperature of 25◦C, decides to pour half the amount of potato in the boiling water and the other half in the burning oil. a) Determine the temperature of the thermal equilibrium between the pore potatoes in the water, and the same for nocao in the oil, considering each cases as isolated systems. (b) Explain why the thermal equilibrium temperatures in both cases are almost the same, mention the physical fundamentals that characterize that result. information in the image respectively: water density: oil density:

Elements Of Electromagnetics
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ISBN:9780190698614
Author:Sadiku, Matthew N. O.
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Calorimetry In a kitchen there are two identical pans that have been previously heated, one of the pans is filled with 1/2 liter of Water at 100◦C and the other with 1/2 liter of oil at 130◦C. After that, no there is more fire that keeps introducing heat to both liquids. In that instant, a person who had cut 300 grams of potato into small cubes at a temperature of 25◦C, decides to pour half the amount of potato in the boiling water and the other half in the burning oil.

a) Determine the temperature of the thermal equilibrium between the pore potatoes in the water, and the same for nocao in the oil, considering each cases as isolated systems.

(b) Explain why the thermal equilibrium temperatures in both cases are almost the same, mention the physical fundamentals that characterize that result.

information in the image respectively:

water density:

oil density:

specific heat of water:

specific oil heat:

specific heat of the potato:

Água <4
Azeite
Aquecer
Aquecer
Estriar
Estriar
Transcribed Image Text:Água <4 Azeite Aquecer Aquecer Estriar Estriar
1,00 g/ml;
= 0,87 g/ml;
J
= 4186
kg.°C
J
= 2000
kg .°C
J
= 5530
kg .°C
Transcribed Image Text:1,00 g/ml; = 0,87 g/ml; J = 4186 kg.°C J = 2000 kg .°C J = 5530 kg .°C
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