0. A particle moves along the x-axis. The velocity of the particle at time t is given by v(t) = 4 If the %3D t+1 position of the particle is x 1 when t = 2, what is the position of the particle when t = 4 ? (A) 0.617 (B) 0.647 (C) 1.353 (D) 5.713

Q: cos4t-cos2t 12. F(t) = %3D t

A: Given that F(t)=cos 4t-cos 2tt The formula for cos 2t is cos 2t=2cos2t-1 Now, cos 4t=cos 22t…

Q: Differentiate. y= In [(x +2)° (x + 5 (x+ 7)°] [In [x+ 2)° (x +5)*(x + 7) ]] =O dx

A:

Q: Given f, S(2)dx = 4, find f,(35(2)+2) dx. S,(35(x)+2)dx.

A:

Q: Differentiate the function. 6. 2. y = .2 x +1 Choose the correct setup below to differentiate the…

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Q: For f(x) = x? – 5x - 6, find f(2), f'(2), and f(3) – f(2). f(2) = a. b. f'(2) %3D c. f(3) – f(2) -

A: The given function is fx=x2-5x-6

Q: 2e2x) when x=0 and y=3. dx Compute

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Q: O Find (a) |VT-x)/x dx, (c) (4-x*y² dx. Ans, ía) 1/60, (/) x/2. (c) 31

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Q: Suppose Find the value of f(10). f(10) = _. d _ƒ(x) = 6x, f(1) = 8. dx

A:

Q: 1.557 B) In (x) dx + | (2 – x) dx 1.557

A: Given : The equations of the curves are y = ln (x) and y = 2 - x and about x - axis.

Q: The windchill index announced during the winter by the weather bureau measures how cold it "feels"…

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Q: SSx = 172.5, SSY = 80.6, and ∑[(X – Mx) (Y – MY)] = 95.33, r =  A. .08. B. .01 C. –.81. D. .81.

A: SSx = 172.5 SSY = 80.6 and ∑[(X – Mx) (Y – MY)] = 95.33

Q: 4. (a) Find dx (b) Using the result from part (a), evaluate. x So (1 + 22)3/2 (1+22)3/2 dx.

A: ANSWER : (a) ​  ANSWER : (b) ​

Q: y-4=t/16 is correct, rather than t/8 in this question, right?

A: Solutions

Q: (#9) S x2 dx V16-x²

A:

Q: .243 Find 5*5x²f (x²)dx if + f(r)dt = m. Select one: a. m5 b. 5m C. m d. 625m

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Q: Find the values of a and b such that a = b + [¹ f(x) dx − [*f(x) dx = f*f(x) dx. - 11

A: Given,