**Problem 3:** Two stones are thrown vertically upward with matching initial velocities of 48 ft/s at time \( t = 0 \). One stone is thrown from the edge of a bridge that is 32 ft above the ground, and the other stone is thrown from ground level. The height of the stone thrown from the bridge after \( t \) seconds is \( f(t) = -16t^2 + 48t + 32 \), and the height of the stone thrown from the ground after \( t \) seconds is \( g(t) = -16t^2 + 48t \). (a) Show that the stones reach their high points at the same time. (b) How much higher does the stone thrown from the bridge go than the stone thrown from the ground? (c) When do the stones strike the ground and with what velocities? **Problem 4:** A stone is thrown from the edge of a bridge that is 48 ft above the ground with an initial velocity of 32 ft/s. The height of this stone above the ground \( t \) seconds after it is thrown is \( f(t) = -16t^2 + 32t + 48 \). If a second stone is thrown from the ground, then its height above the ground after \( t \) seconds is given by \( g(t) = -16t^2 + v_0t \), where \( v_0 \) is the initial velocity of the second stone. Determine the value \( v_0 \) so that both the stones reach the same high point.