Use the graph of f and g. p(x) = f(x)g(x) f(x) g(x) q(x) 10 2 -2 2 6 10 -2 (a) Find p'(9). p'(9) = (b) Find q'(1). q'(1) = %3D 4.

Q: Differentiate. ax + b f(x) %3D Cx + d f '(x) =

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Q: 4 X- - 5x +4. %3D Find f'(x), f"(x), and f (x) for f(x) = f'(x) = f"(x) =

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Q: If f' (4) = -9 and g ' (4) = -5, find (a) h'(4), if h(x) = 10f(x) + 2. %3D h'(4) = %3D (b) F'(4), if…

A: Recall: (αf(x)±βg(x))' = α f'(x)±β g'(x) ; where α and β are real numbers.

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A: Here we have been given that f(x)=3x2+7x+2x-(i)Our Aim is to find f'(x) and f'(16)=?

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Q: Find f(x) if f'(x) =2/+.

A: The derivative of f(x) is given, so to find f(x) we need to integrate f'(x)=2x+5x6. The integration…

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Q: Use the graph of f and g. p(x) = f(x)g(x) %3D f(x) q(x) = g(x) %3D y 10 8 f 4 2 -2 2 4 6. 8 10

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Q: uppose P(x) represents the profit on the sale of x DVDs. If P(1000) = 3000 and P'(1000) = −3, what…

A: Given that  Px  represents the profit on the sale of DVDs. P'1000  is our profit for selling 1000…

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Q: y=−x/3+4/3  the xx intercept = (   ,0) yy intercept = (0,)   The slope =

A: Given the equation of line  y = -x/3 + 4/3  we need to find xx intercept , yy intercept and slope of…

Q: Consider the function f(x) = (g(x)h(x))^2 and the following function values: f(5) = 1 g(5) = −1…

A: Given: f(x)=[g(x)h(x)]2f(5)=1g(5)=−1h(5)=2g'(5)=3h'(5)=4f'(5)=?

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Q: Find f'(a). f(x) = 7x - 8x + 6| %3D

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Q: Please

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Q: f (x) = (x³ – 5x + 2)(x² + x – 7); find f'(x) %3D

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Q: For the function f(x) = , find f'(x). 4x 7-x' f (x) = Answer: %3D

A: The given function is: fx=4x7-x      .....(1) To find the value of f-1x

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A: Given graph for f

Q: If f(x) = x2/(4 + x), find f "(2). f "(2) =

A: f(x) = x2 /(4+x)  f'(x) = [(4+x)(2x) - x2(1)] / (4+x)2  = (8x+2x2 - x2)/(4+x)2 = (8x+x2)/(4+x)2…

Q: If f(x) = 7x² f'(2) = f''(x) = f''(2) = 8e, find:

A: The given function is fx=7x2-8ex

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A: Given :p(x)=9x7x2+1

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Q: Find f'(a). f(x) = 3x2 - 4x + 4

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Q: Find h(x) if h'(x)= h(x): 5x (6-x²)² X and h(1) = -6.

A: NOTE: Refresh your page if you can't see any equations. . here we have take integration on both…