An object traveling in a straight line has position x(t) at time t. If the initial position is x(0) = 2 and the velocity of the object is v(t) = V1+7, wat is the position of the object at time t = 3? (B) 2.154 (C) 4,512 (D) 6,512 (E) 17.408 コC OB Question 8 The maximum acceleration attained on the interval 0 SI33 by the particle whose velocity is given by v(t)=t-3t +12t +4 is s (B) 12 (C) 14
An object traveling in a straight line has position x(t) at time t. If the initial position is x(0) = 2 and the velocity of the object is v(t) = V1+7, wat is the position of the object at time t = 3? (B) 2.154 (C) 4,512 (D) 6,512 (E) 17.408 コC OB Question 8 The maximum acceleration attained on the interval 0 SI33 by the particle whose velocity is given by v(t)=t-3t +12t +4 is s (B) 12 (C) 14
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
![An object traveling in a straight line has position x(t) at time t. If the initial position is x(0) = 2 and the
velocity of the object is v(t) = V1+7, wat is the position of the object at time t = 3?
(B) 2.154
(C) 4,512
(D) 6,512
(E) 17.408
コC
OB
Question 8
The maximum acceleration attained on the interval 0 SI33 by the particle whose velocity is given
by v(t)=t-3t +12t +4 is
s
(B) 12
(C) 14](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F318028df-d911-4e4d-a91c-645448b07ccb%2F963cdf68-f061-4024-9179-855f0c6d6386%2Fzlsd77.jpeg&w=3840&q=75)
Transcribed Image Text:An object traveling in a straight line has position x(t) at time t. If the initial position is x(0) = 2 and the
velocity of the object is v(t) = V1+7, wat is the position of the object at time t = 3?
(B) 2.154
(C) 4,512
(D) 6,512
(E) 17.408
コC
OB
Question 8
The maximum acceleration attained on the interval 0 SI33 by the particle whose velocity is given
by v(t)=t-3t +12t +4 is
s
(B) 12
(C) 14
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