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**Solve the polynomial inequality and graph the solution set on a real number line. Express the solution set in interval notation.** Given inequality: \(x^2 - 8x + 16 < 0\) **Solve the inequality: What is the solution set? Select the correct choice below and, if necessary, fill in the answer box to complete your choice.** - \( \text{A. The solution set is } \ \underline{\hspace{2em}}. \) *(Simplify your answer. Type your answer in interval notation. Type an exact answer, using radicals as needed. Use integers or fractions for any numbers in the expression.)* - \(\text{B. The solution set is the empty set.}\) **Choose the correct graph below.** - \(\text{O A.}\) Graph line displays a segment from \(-12\) to \(4\), including both endpoints, indicated with a solid blue line. - \(\text{O B.}\) Graph line displays a solid blue arrow extending infinitely to the right from \(4\). - \(\text{O C.}\) Graph line displays a solid blue arrow extending infinitely to the left from \(4\). - \(\text{O D.}\) Graph line displays a solid blue arrow extending infinitely to the right from \(-8\). - \(\text{O E.}\) Graph line displays a segment from \(-12\) to \(0\), including both endpoints, indicated with a solid blue line. - \(\text{O F.}\) Graph line displays a segment from \(4\) to \(12\), including both endpoints, indicated with a solid blue line. **Instructions:** Click to select your answer: - Save for Later The solution to the inequality \(x^2 - 8x + 16 < 0\) results in an empty set since \( (x-4)^2 = 0 \) implies there are no x-values that satisfy the inequality.

**Solve the polynomial inequality and graph the solution set on a real number line. Express the solution set in interval notation.** Given inequality: \(x^2 - 8x + 16 < 0\) **Solve the inequality: What is the solution set? Select the correct choice below and, if necessary, fill in the answer box to complete your choice.** - \( \text{A. The solution set is } \ \underline{\hspace{2em}}. \) *(Simplify your answer. Type your answer in interval notation. Type an exact answer, using radicals as needed. Use integers or fractions for any numbers in the expression.)* - \(\text{B. The solution set is the empty set.}\) **Choose the correct graph below.** - \(\text{O A.}\) Graph line displays a segment from \(-12\) to \(4\), including both endpoints, indicated with a solid blue line. - \(\text{O B.}\) Graph line displays a solid blue arrow extending infinitely to the right from \(4\). - \(\text{O C.}\) Graph line displays a solid blue arrow extending infinitely to the left from \(4\). - \(\text{O D.}\) Graph line displays a solid blue arrow extending infinitely to the right from \(-8\). - \(\text{O E.}\) Graph line displays a segment from \(-12\) to \(0\), including both endpoints, indicated with a solid blue line. - \(\text{O F.}\) Graph line displays a segment from \(4\) to \(12\), including both endpoints, indicated with a solid blue line. **Instructions:** Click to select your answer: - Save for Later The solution to the inequality \(x^2 - 8x + 16 < 0\) results in an empty set since \( (x-4)^2 = 0 \) implies there are no x-values that satisfy the inequality.

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Solve the polynomial inequality and graph the solution set on a real number line. Express the solution set in interval notation.** Given inequality: \(x^2 - 8x + 16 < 0\) **Solve the inequality: What is the solution set? Select the correct choice below and, if necessary, fill in the answer box to complete your choice.** - \( \text{A. The solution set is } \ \underline{\hspace{2em}}. \) *(Simplify your answer. Type your answer in interval notation. Type an exact answer, using radicals as needed. Use integers or fractions for any numbers in the expression.)* - \(\text{B. The solution set is the empty set.}\) **Choose the correct graph below.** - \(\text{O A.}\) Graph line displays a segment from \(-12\) to \(4\), including both endpoints, indicated with a solid blue line. - \(\text{O B.}\) Graph line displays a solid blue arrow extending infinitely to the right from \(4\). - \(\text{O C.}\) Graph line displays a solid blue arrow extending infinitely to the left from \(4\). - \(\text{O D.}\) Graph line displays a solid blue arrow extending infinitely to the right from \(-8\). - \(\text{O E.}\) Graph line displays a segment from \(-12\) to \(0\), including both endpoints, indicated with a solid blue line. - \(\text{O F.}\) Graph line displays a segment from \(4\) to \(12\), including both endpoints, indicated with a solid blue line. **Instructions:** Click to select your answer: - Save for Later The solution to the inequality \(x^2 - 8x + 16 < 0\) results in an empty set since \( (x-4)^2 = 0 \) implies there are no x-values that satisfy the inequality.
Transcribed Image Text:**Solve the polynomial inequality and graph the solution set on a real number line. Express the solution set in interval notation.** Given inequality: \(x^2 - 8x + 16 < 0\) **Solve the inequality: What is the solution set? Select the correct choice below and, if necessary, fill in the answer box to complete your choice.** - \( \text{A. The solution set is } \ \underline{\hspace{2em}}. \) *(Simplify your answer. Type your answer in interval notation. Type an exact answer, using radicals as needed. Use integers or fractions for any numbers in the expression.)* - \(\text{B. The solution set is the empty set.}\) **Choose the correct graph below.** - \(\text{O A.}\) Graph line displays a segment from \(-12\) to \(4\), including both endpoints, indicated with a solid blue line. - \(\text{O B.}\) Graph line displays a solid blue arrow extending infinitely to the right from \(4\). - \(\text{O C.}\) Graph line displays a solid blue arrow extending infinitely to the left from \(4\). - \(\text{O D.}\) Graph line displays a solid blue arrow extending infinitely to the right from \(-8\). - \(\text{O E.}\) Graph line displays a segment from \(-12\) to \(0\), including both endpoints, indicated with a solid blue line. - \(\text{O F.}\) Graph line displays a segment from \(4\) to \(12\), including both endpoints, indicated with a solid blue line. **Instructions:** Click to select your answer: - Save for Later The solution to the inequality \(x^2 - 8x + 16 < 0\) results in an empty set since \( (x-4)^2 = 0 \) implies there are no x-values that satisfy the inequality.
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